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- Locations: Bengaluru, Hyderabad
This page collects Swiggy placement papers from 2024 with previous-year questions, solutions, and the 2024 exam pattern. It is useful when you want real drive history: what the OA looked like, which question types repeated, and how solutions were approached. Work through the papers below to build speed and accuracy, then compare against newer 2025 material so your prep matches both established Swiggy patterns and the latest shifts.
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Coding Problem 1 | 1 | 30 min | Medium | Arrays, strings |
| Coding Problem 2 | 1 | 30 min | Hard | Trees, graphs, DP |
| Debugging | 1 | 30 min | Medium | Code fixes |
Total: 3 problems, 90 minutes
Platform: HackerRank or Swiggy’s internal platform
Languages Allowed: Java, C++, Python, Go
Success Rate: ~10-15% cleared OA and advanced to interviews
This section contains practice questions styled on Swiggy placement papers 2024 (previous-year pattern), with worked solutions. Use them as timed sectional drills - from student reports drives vary by college and role, so treat this as a high-signal practice bank, not an official paper dump.
Problem Statement: Given a string, return it reversed.
Example:
Input: "placement"Output: "tnemecalp"Solution (Java):
public String reverse(String s) { return new StringBuilder(s).reverse().toString();}Time Complexity: O(n)
Space Complexity: O(n)
Problem Statement: You can climb 1 or 2 steps. How many distinct ways to climb n stairs?
Example:
Input: n = 4Output: 5Solution (Java):
public int climbStairs(int n) { if (n <= 2) return n; int a = 1, b = 2; for (int i = 3; i <= n; i++) { int c = a + b; a = b; b = c; } return b;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Return the first non-repeating character in a string, or ‘_’ if none.
Example:
Input: "swiss"Output: 'w'Solution (Java):
public char firstUnique(String s) { int[] freq = new int[256]; for (char c : s.toCharArray()) freq[c]++; for (char c : s.toCharArray()) if (freq[c] == 1) return c; return '_';}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Return true if the string reads the same forward and backward (ignore case).
Example:
Input: "Level"Output: trueSolution (Java):
public boolean isPalindrome(String s) { s = s.toLowerCase(); int i = 0, j = s.length() - 1; while (i < j) { if (s.charAt(i++) != s.charAt(j--)) return false; } return true;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Find the contiguous subarray with the largest sum.
Example:
Input: [-2, 1, -3, 4, -1, 2, 1, -5, 4]Output: 6 // [4, -1, 2, 1]Solution (Java):
public int maxSubArray(int[] nums) { int best = nums[0], cur = nums[0]; for (int i = 1; i < nums.length; i++) { cur = Math.max(nums[i], cur + nums[i]); best = Math.max(best, cur); } return best;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Rotate the array to the right by k steps.
Example:
Input: [1,2,3,4,5,6,7], k = 3Output: [5,6,7,1,2,3,4]Solution (Java):
public void rotate(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1);}void reverse(int[] a, int l, int r) { while (l < r) { int t = a[l]; a[l++] = a[r]; a[r--] = t; }}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Merge two sorted linked lists and return a new sorted list.
Example:
Input: 1→2→4 , 1→3→4Output: 1→1→2→3→4→4Solution (Java):
public ListNode mergeTwoLists(ListNode a, ListNode b) { ListNode dummy = new ListNode(0), cur = dummy; while (a != null && b != null) { if (a.val <= b.val) { cur.next = a; a = a.next; } else { cur.next = b; b = b.next; } cur = cur.next; } cur.next = (a != null) ? a : b; return dummy.next;}Time Complexity: O(n + m)
Space Complexity: O(1)
Solution:
Unbalanced partitions (already sorted with bad pivot) → O(n²).
Answer: O(n²)
Solution:
TCP is connection-oriented; UDP is connectionless.
Answer: TCP
Solution:
OS uses demand paging (and sometimes segmentation) to implement virtual memory.
Answer: Demand paging
Solution:
HAVING filters aggregates; WHERE filters rows before grouping.
Answer: HAVING
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Success Tips:
For detailed interview experiences, visit Swiggy Interview Experience page.