Zensar 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Zensar placement papers from 2025 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Zensar patterns and recent shifts.
Zensar 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
Zensar 2025 coding
DSA practice aligned to Zensar online assessments
Zensar interview experience
Round structure and tips from student reports
Zensar prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
A shopkeeper marks his goods 20% above cost price but allows a discount of 10%. What is his profit percentage?
Let CP = ₹100 Marked Price (MP) = 100 + 20% of 100 = ₹120 Discount = 10% of 120 = ₹12 Selling Price (SP) = 120 - 12 = ₹108 Profit = 108 - 100 = ₹8 Profit % = (8/100) × 100 = 8%
Reasoning
Series: 3, 7, 15, 31, 63, ?
×2+1 pattern: 63×2+1 = 127.
Quantitative
A person travels 3/8 of a journey by train, 1/4 by bus, and the remaining 120 km by car. Find the total distance of the journey.
Let total distance = D km By train = 3D/8 By bus = D/4 = 2D/8 By car = 120 km Total: 3D/8 + 2D/8 + 120 = D 5D/8 + 120 = D 120 = D - 5D/8 = 3D/8 D = 120 × 8/3 = 320 km
Verbal
Antonym of "Temporary":
Temporary ↔ permanent.
Reasoning
Find the next number: 1, 3, 6, 10, 15, ?
Correct answer: 21
Reasoning
If every letter is shifted +2 in the alphabet, BOOK becomes:
Each letter +2 → DQQM.
Quantitative
The ratio of boys to girls in a class is 3:2. If there are 30 students, how many are girls?
Correct answer: 12 girls
Reasoning
All pens are books. Some books are papers. Conclusion: Some pens are papers.
No definite overlap between pens and papers.
Reasoning
If P means +, Q means −, R means ×, then 18 R 2 P 6 Q 4 = ?
18 × 2 + 6 − 4 = 36 + 6 − 4 = 38.
Verbal
Problem: Find the synonym of "MAGNIFICENT": a) Ordinary b) Splendid c) Small d) Ugly
Magnificent means impressively beautiful or grand, so "Splendid" is the synonym.
Quantitative
A shopkeeper marks an item 30% above cost price and gives 10% discount. Find his profit percentage.
Let CP = ₹100 Marked Price = ₹130 Discount = 10% of ₹130 = ₹13 Selling Price = ₹130 - ₹13 = ₹117 Profit = ₹117 - ₹100 = ₹17 Profit % = (17/100) × 100 = 17%
Verbal
Neither the teacher nor the students _____ present.
Verb agrees with nearer subject (students) → were.
Verbal
Synonym of "Vivid":
Vivid means bright.
Quantitative
What does "Hit the nail on the head" mean?
"Hit the nail on the head" means to be exactly right or accurate.
Quantitative
In what ratio should water be mixed with milk costing ₹20 per liter to get a mixture worth ₹15 per liter?
Correct answer: 1:3
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Aptitude / logical | Quant, reasoning, sometimes verbal | Timed sectional accuracy |
| Coding / programming logic | Easy-medium DSA or output-style MCQs | Handle tricky inputs |
| Technical interview | OOPs, DBMS, OS, projects | Explain aloud |
| HR | Fit, location, intent | A few real examples ready |
First round: Zensar Assessment
Skills emphasized: Aptitude, coding, communication
Languages: Java, Python, SQL
These are practice-style questions aligned to patterns students report for Zensar drives around 2025. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: Find the next term: 2, 6, 12, 20, 30, ?
Solution: Pattern: 1×2, 2×3, 3×4, 4×5, 5×6, 6×7. Next = 6 × 7 = 42.
Answer: 42
Problem: What is the probability of drawing an ace from a standard 52-card deck?
Solution: There are 4 aces in 52 cards. Probability = 4/52 = 1/13.
Answer: 1/13
Problem: A number is increased by 20% and then decreased by 20%. What is the net percentage change?
Solution: Start with 100 → 120 → 96. Net change = 4% decrease. Formula: successive +a then −a gives −(a²/100)% = −4%.
Answer: 4% decrease
Problem: If the price of an item rises by 25%, by what percent should consumption fall so that expenditure stays the same?
Solution: Required reduction = r/(100+r) × 100 with r = 25. = 25/125 × 100 = 20%.
Answer: 20%
Problem: An article is marked 40% above cost and sold after a 10% discount. Find the profit percent.
Solution: SP = CP × 1.4 × 0.9 = 1.26 CP. Profit = 26%.
Answer: 26%
Problem: An article sold at 10% loss would give 5% profit if sold for ₹60 more. Find the cost price.
Solution: 0.9P + 60 = 1.05P 60 = 0.15P P = 60 / 0.15 = ₹400.
Answer: ₹400
Problem: Eight workers finish a job in 10 days. How many days will 10 workers take for the same job (same pace)?
Solution: Total man-days = 8 × 10 = 80. Days for 10 workers = 80 / 10 = 8 days.
Answer: 8 days
Problem: A vehicle travels at 60 km/h for 2.5 hours. How far does it go?
Solution: Distance = speed × time = 60 × 2.5 = 150 km.
Answer: 150 km
Problem: Statements: All engineers are graduates. Some graduates are managers. Conclusion: Some engineers are managers. Does it follow?
Solution: The ‘some graduates’ who are managers need not overlap with the engineers. The conclusion does not follow necessarily.
Answer: Does not follow
Problem: A person walks 5 km north, then 3 km east, then 5 km south. How far is he from the start, and in which direction?
Solution: North 5 and south 5 cancel. He is 3 km east of the start.
Answer: 3 km east
Problem: Find the next number: 3, 9, 27, 81, ?
Solution: Each term is multiplied by 3. Next = 81 × 3 = 243.
Answer: 243
Problem: Five friends sit in a row. A is to the left of B but right of C. D is to the right of B and left of E. Who is in the middle?
Solution: Order from left to right: C, A, B, D, E. The middle seat is B.
Answer: B
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Find the first non-repeating character in a string and return its index, or -1 if none exists.
Approach: Count frequencies in one pass (hash map or array of 26 for lowercase). Second pass returns the first index with count 1.
Complexity: O(n) time
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Design a stack that supports push, pop, top, and getMin in average O(1) time.
Approach: Keep a parallel min-stack (or store pairs). When pushing, also push the new minimum. When popping, pop both stacks.
Complexity: O(1) per operation amortized
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array, find the contiguous subarray with the largest sum and return that sum. Example: [-2,1,-3,4,-1,2,1,-5,4] → 6 (from [4,-1,2,1]).
Approach: Keep a running sum. If the running sum drops below 0, reset it to 0 before taking the next element (or track the best ending-here value). Track the global maximum as you scan once from left to right.
Complexity: O(n) time, O(1) extra space
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a mutable character array representing a string, reverse it in place without allocating another array of the same size.
Approach: Use two pointers at the start and end. Swap characters, then move inward until the pointers meet. Watch empty and single-character inputs.
Complexity: O(n) time, O(1) extra space
Zensar tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Zensar, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, Python, SQL.
| Area | Why it matters at Zensar |
|---|---|
| Aptitude | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| IT Services, Experience Tech awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |