Tech Mahindra 2025 papers
Latest Tech Mahindra placement papers with current year questions
This page collects Tech Mahindra placement papers from 2024 with previous-year questions, solutions, and the 2024 exam pattern. It is useful when you want real drive history: what the OA looked like, which question types repeated, and how solutions were approached. Work through the papers below to build speed and accuracy, then compare against newer 2025 material so your prep matches both established Tech Mahindra patterns and the latest shifts.
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Quantitative Aptitude | 15-20 | 30 min | Medium | Percentages, ratios, time & work |
| Logical Reasoning | 15-20 | 30 min | Medium | Series, syllogism, puzzles |
| Verbal Ability | 10-15 | 15 min | Medium | Grammar, comprehension |
| Technical | 10-15 | 10 min | Medium | Programming, DBMS, OOPs |
| Coding | 1-2 | 5 min | Medium-Hard | Arrays, strings, basic algorithms |
Total: 50-60 questions, 90 minutes
Platform: Tech Mahindra assessment platform
Languages Allowed: C, C++, Java, Python
Success Rate: ~20-25% cleared assessment and advanced to interviews
This section contains practice questions styled on Tech Mahindra placement papers 2024 (previous-year pattern), with worked solutions. Use them as timed sectional drills - from student reports drives vary by college and role, so treat this as a high-signal practice bank, not an official paper dump.
Solution:
Let CP = 100. MP = 140. SP after 10% discount = 126.
Profit % = 126 − 100 = 26%.
Answer: 26%
Solution:
Together rate = 1/8. B’s rate = 1/24.
A’s rate = 1/8 − 1/24 = (24−8)/(8×24) = 16/192. Days for A alone = 192/16 = 12 days.
Answer: 12 days
Solution:
Speed = distance/time = 240/16 m/s = (240/16) × (18/5) = 54 km/h.
Answer: 54 km/h
Solution:
Let ages be 2x and 3x.
(2x + 6)/(3x + 6) = 3/4 4(2x + 6) = 3(3x + 6) 8x + 24 = 9x + 18 x = 6 A’s age = 2×6 = 12 years.
Answer: 12 years
Solution:
Pattern: n(n+1): 1×2, 2×3, 3×4, 4×5, 5×6 → next 6×7
Next term = 42.
Answer: 42
Solution:
From the statements, pens⊆items and some items overlap cheap. That does not force some pens to be cheap, and ‘all items are pens’ reverses the first statement wrongly.
Neither conclusion follows.
Answer: Neither I nor II follows
Solution:
‘Voluntary’ means roughly the opposite of Compulsory.
Answer: Compulsory
Solution:
‘Neither’ is singular → verb should be has, not have.
Correct: Neither of the boys has submitted his/their assignment.
Answer: have → has
Problem Statement: Merge two sorted linked lists and return a new sorted list.
Example:
Input: 1→2→4 , 1→3→4Output: 1→1→2→3→4→4Solution (Java):
public ListNode mergeTwoLists(ListNode a, ListNode b) { ListNode dummy = new ListNode(0), cur = dummy; while (a != null && b != null) { if (a.val <= b.val) { cur.next = a; a = a.next; } else { cur.next = b; b = b.next; } cur = cur.next; } cur.next = (a != null) ? a : b; return dummy.next;}Time Complexity: O(n + m)
Space Complexity: O(1)
Problem Statement: Rotate the array to the right by k steps.
Example:
Input: [1,2,3,4,5,6,7], k = 3Output: [5,6,7,1,2,3,4]Solution (Java):
public void rotate(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1);}void reverse(int[] a, int l, int r) { while (l < r) { int t = a[l]; a[l++] = a[r]; a[r--] = t; }}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Return the first non-repeating character in a string, or ‘_’ if none.
Example:
Input: "swiss"Output: 'w'Solution (Java):
public char firstUnique(String s) { int[] freq = new int[256]; for (char c : s.toCharArray()) freq[c]++; for (char c : s.toCharArray()) if (freq[c] == 1) return c; return '_';}Time Complexity: O(n)
Space Complexity: O(1)
Based on candidate experiences from 2024 Tech Mahindra interviews:
2024 Interview Process:
Common 2024 Interview Topics:
Success Tips:
For detailed interview experiences, visit Tech Mahindra Interview Experience page.
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