Microsoft 2024 papers
Previous year Microsoft placement papers with questions and solutions
This page is a working set of Microsoft placement papers from 2025: from student reports questions, the 2025 online assessment pattern, and step-by-step solutions. Use it to see what Microsoft actually asked in the latest cycle, how hard the rounds were, and which themes (DSA, system design, aptitude, or role-specific topics) mattered most. Practice the problems below under timed conditions, then cross-check with the interview and preparation guides if you are targeting an upcoming Microsoft drive.
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Coding Problems | 3-4 | 60-90 min | Medium-Hard | Arrays, trees, graphs, DP |
Total: 3-4 problems, 60-90 minutes
Platform: Microsoft Codility or HackerRank
Languages Allowed: C++, Java, Python, C#
Success Rate: ~15-20% cleared OA and advanced to interviews
This section contains practice questions styled on Microsoft placement papers 2025 (recent-cycle pattern), with worked solutions. Use them as timed sectional drills - from student reports drives vary by college and role, so treat this as a high-signal practice bank, not an official paper dump.
Problem Statement: Return true if the linked list has a cycle.
Example:
Input: 3→2→0→-4→(back to 2)Output: trueSolution (Java):
public boolean hasCycle(ListNode head) { ListNode slow = head, fast = head; while (fast != null && fast.next != null) { slow = slow.next; fast = fast.next.next; if (slow == fast) return true; } return false;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Given a string, return it reversed.
Example:
Input: "placement"Output: "tnemecalp"Solution (Java):
public String reverse(String s) { return new StringBuilder(s).reverse().toString();}Time Complexity: O(n)
Space Complexity: O(n)
Problem Statement: You can climb 1 or 2 steps. How many distinct ways to climb n stairs?
Example:
Input: n = 4Output: 5Solution (Java):
public int climbStairs(int n) { if (n <= 2) return n; int a = 1, b = 2; for (int i = 3; i <= n; i++) { int c = a + b; a = b; b = c; } return b;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Rotate the array to the right by k steps.
Example:
Input: [1,2,3,4,5,6,7], k = 3Output: [5,6,7,1,2,3,4]Solution (Java):
public void rotate(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1);}void reverse(int[] a, int l, int r) { while (l < r) { int t = a[l]; a[l++] = a[r]; a[r--] = t; }}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Return true if the string reads the same forward and backward (ignore case).
Example:
Input: "Level"Output: trueSolution (Java):
public boolean isPalindrome(String s) { s = s.toLowerCase(); int i = 0, j = s.length() - 1; while (i < j) { if (s.charAt(i++) != s.charAt(j--)) return false; } return true;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Find the contiguous subarray with the largest sum.
Example:
Input: [-2, 1, -3, 4, -1, 2, 1, -5, 4]Output: 6 // [4, -1, 2, 1]Solution (Java):
public int maxSubArray(int[] nums) { int best = nums[0], cur = nums[0]; for (int i = 1; i < nums.length; i++) { cur = Math.max(nums[i], cur + nums[i]); best = Math.max(best, cur); } return best;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Find the longest common prefix string amongst an array of strings.
Example:
Input: ["flower","flow","flight"]Output: "fl"Solution (Java):
public String longestCommonPrefix(String[] strs) { if (strs.length == 0) return ""; String pref = strs[0]; for (int i = 1; i < strs.length; i++) { while (!strs[i].startsWith(pref)) { pref = pref.substring(0, pref.length() - 1); if (pref.isEmpty()) return ""; } } return pref;}Time Complexity: O(S)
Space Complexity: O(1)
Solution:
Each step halves the search space → O(log n).
Answer: O(log n)
Solution:
This is the definition of Encapsulation (often paired with abstraction in interviews).
Answer: Encapsulation
Solution:
Unbalanced partitions (already sorted with bad pivot) → O(n²).
Answer: O(n²)
Solution:
1NF: atomic values. 2NF: no partial dependency. 3NF: no transitive dependency.
Answer: 3NF
Based on recent candidate experiences from 2025 Microsoft interviews:
2025 Interview Process:
2025 Interview Trends:
Common 2025 Interview Topics:
2025 Interview Questions Examples:
Success Tips:
Difficulty Rating: 3.1/5
For detailed interview experiences from 2025, visit Microsoft Interview Experience page.
Microsoft 2024 papers
Previous year Microsoft placement papers with questions and solutions
Microsoft coding questions
Complete collection of Microsoft coding problems with solutions
Microsoft interview experience
Real interview experiences from successful candidates
Microsoft preparation guide
Comprehensive preparation strategy for Microsoft placement
Microsoft main page
Complete Microsoft placement guide with eligibility, process, and salary
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