Jio 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Jio placement papers from 2026 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Jio patterns and recent shifts.
Jio 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
Jio 2026 coding
DSA practice aligned to Jio online assessments
Jio interview experience
Round structure and tips from student reports
Jio prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
Price rises by 25%. By what % should consumption fall to keep expenditure the same?
Reduction = 25/(100+25)×100 = 20%.
Quantitative
A car covers 180 km in 3 hours. Average speed is:
Speed = 180/3 = 60 km/h.
Reasoning
Statements: Some cats are dogs. All dogs are animals. Conclusion: Some cats are animals. Is the conclusion valid?
Correct answer: Valid
Verbal
Choose correct: The news _____ good.
"News" is singular → is.
Quantitative
What does "Break the ice" mean?
"Break the ice" means to initiate conversation in a social setting.
Verbal
Fill: Neither the teacher nor the students _____ present.
With neither…nor, verb agrees with nearer subject (students) → were.
Quantitative
A man can row 7 km/h in still water. If the river is flowing at 3 km/h, how long will it take him to row 12 km downstream?
Speed in still water = 7 km/h Speed of stream = 3 km/h Downstream speed = 7 + 3 = 10 km/h Time = Distance/Speed = 12/10 = 1.2 hours = 1 hour 12 minutes
Quantitative
A train 120 m long crosses a pole in 8 s. Speed in km/h:
Speed = 120/8 = 15 m/s = 54 km/h.
Verbal
Three pipes A, B, C can fill a tank in 12, 15, and 20 hours respectively. If all three are opened together, how long will it take to fill the tank?
A's rate = 1/12 per hour B's rate = 1/15 per hour C's rate = 1/20 per hour Combined rate = 1/12 + 1/15 + 1/20 = (5+4+3)/60 = 12/60 = 1/5 per hour Time = 1 / (1/5) = 5 hours
Reasoning
A walks 10m North, turns right walks 5m, turns right walks 10m. Direction from start?
Correct answer: East (5m east of starting point)
Reasoning
If letter positions are summed (A=1…Z=26), RED equals:
Sum of positions = 27.
Reasoning
If every letter is shifted +2 in the alphabet, CANDLE becomes:
C→E, A→C, N→P, D→F, L→N, E→G → ECPFNG.
Reasoning
If BOOK is coded as 43, then PEN is coded as:
B+O+O+K = 2+15+15+11 = 43; P+E+N = 16+5+14 = 35.
Quantitative
A person travels first half of distance at 40 km/hr and second half at 60 km/hr. Find average speed.
Let total distance = 2D Time for first half = D/40 Time for second half = D/60 Total time = D/40 + D/60 = D(3+2)/120 = 5D/120 = D/24 Average speed = 2D / (D/24) = 48 km/hr
Verbal
Synonym of "Abundant":
Abundant means plentiful.
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Technical / domain | Syllabus aligned to the notification | Topic checklist |
| Aptitude | Quant + reasoning | Speed with accuracy |
| Interview | Subject depth + projects | Clear fundamentals |
First round: Jio Online Assessment
Skills emphasized: Aptitude, coding, telecom/CS basics
Languages: Java, Python, C++
These are practice-style questions aligned to patterns students report for Jio drives around 2026. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: Find simple interest on ₹5000 at 8% per annum for 3 years.
Solution: SI = 5000 × 8 × 3 / 100 = ₹1200.
Answer: ₹1200
Problem: A boat’s speed in still water is 15 km/h and the stream is 3 km/h. How long to cover 36 km upstream?
Solution: Upstream speed = 15 − 3 = 12 km/h. Time = 36 / 12 = 3 hours.
Answer: 3 hours
Problem: A mixture has milk and water in the ratio 4:1. If 5 litres of water are added to 20 litres of mixture, what is the new milk:water ratio?
Solution: In 20 L: milk = 16 L, water = 4 L. After adding 5 L water: milk 16, water 9. Ratio = 16:9.
Answer: 16:9
Problem: Find compound interest on ₹10,000 at 10% per annum for 2 years, compounded annually.
Solution: Amount = 10000 × (1.1)² = 10000 × 1.21 = ₹12,100. CI = 12100 − 10000 = ₹2100. (SI for same period would be ₹2000; the extra ₹100 is interest on first-year interest.)
Answer: ₹2100
Problem: What is the angle between the hour and minute hands at 3:00?
Solution: At 3:00 the hands are exactly 90° apart (one quarter of the circle).
Answer: 90°
Problem: In how many ways can 5 different books be arranged on a shelf?
Solution: Arrangements of 5 distinct items = 5! = 120.
Answer: 120
Problem: If the sum of three consecutive integers is 72, what is the smallest of these integers?
Solution: Let the integers be x, x+1, and x+2.
x + (x+1) + (x+2) = 72 3x + 3 = 72 3x = 69 x = 23
So the integers are 23, 24, and 25.
Answer: 23
Problem: A train 150 meters long passes a pole in 15 seconds. What is its speed in km/h?
Solution: Distance = 150 m = 0.15 km. Time = 15 s = 15/3600 h = 1/240 h. Speed = 0.15 ÷ (1/240) = 0.15 × 240 = 36 km/h.
Faster check: 150/15 = 10 m/s → 10 × 18/5 = 36 km/h.
Answer: 36 km/h
Problem: Find the next number: 3, 9, 27, 81, ?
Solution: Each term is multiplied by 3. Next = 81 × 3 = 243.
Answer: 243
Problem: Five friends sit in a row. A is to the left of B but right of C. D is to the right of B and left of E. Who is in the middle?
Solution: Order from left to right: C, A, B, D, E. The middle seat is B.
Answer: B
Problem: Book is to Reading as Fork is to ?
Solution: A book is used for reading; a fork is used for eating.
Answer: Eating
Problem: Find the odd one out: 3, 5, 7, 9, 11
Solution: 3, 5, 7, and 11 are prime. 9 = 3×3 is composite, so it is the odd one out.
Answer: 9
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Find the first non-repeating character in a string and return its index, or -1 if none exists.
Approach: Count frequencies in one pass (hash map or array of 26 for lowercase). Second pass returns the first index with count 1.
Complexity: O(n) time
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Design a stack that supports push, pop, top, and getMin in average O(1) time.
Approach: Keep a parallel min-stack (or store pairs). When pushing, also push the new minimum. When popping, pop both stacks.
Complexity: O(1) per operation amortized
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array, find the contiguous subarray with the largest sum and return that sum. Example: [-2,1,-3,4,-1,2,1,-5,4] → 6 (from [4,-1,2,1]).
Approach: Keep a running sum. If the running sum drops below 0, reset it to 0 before taking the next element (or track the best ending-here value). Track the global maximum as you scan once from left to right.
Complexity: O(n) time, O(1) extra space
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a mutable character array representing a string, reverse it in place without allocating another array of the same size.
Approach: Use two pointers at the start and end. Swap characters, then move inward until the pointers meet. Watch empty and single-character inputs.
Complexity: O(n) time, O(1) extra space
Jio tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Jio, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, Python, C++.
| Area | Why it matters at Jio |
|---|---|
| Aptitude | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Telecom, Digital Services awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |