Intel 2024 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Intel placement papers from 2024 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Intel patterns and recent shifts.
Intel 2024 aptitude
Quantitative, reasoning, and verbal drills with solutions
Intel 2024 coding
DSA practice aligned to Intel online assessments
Intel interview experience
Round structure and tips from student reports
Intel prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Reasoning
All cats are animals. Some animals are dogs. Therefore, some cats are dogs. Is the conclusion valid?
The conclusion is invalid. While all cats are animals and some animals are dogs, there is no information linking cats directly to dogs. The conclusion cannot be logically derived from the given statements.
Quantitative
If 3x + 5 = 20, then x equals:
3x = 15 → x = 5.
Quantitative
A bank offers a loan of ₹50,000 at 8% per annum simple interest. What is the interest after 2 years?
Correct answer: ₹8,000
Reasoning
Odd one out: Triangle, Square, Circle, Rectangle
Circle has no straight sides.
Verbal
Synonym of "Crucial":
Crucial means important.
Reasoning
Complete the series: AZ, BY, CX, ?
First letter +1, second −1 → DW.
Quantitative
If a number is increased by 20% and then decreased by 15%, what is the net change?
Correct answer: +2% increase
Quantitative
The ratio of ages of A and B is 3:5. After 8 years, the ratio becomes 5:7. Find the present age of A.
Let present ages be 3x and 5x. After 8 years: - A's age: 3x + 8 - B's age: 5x + 8 Given: (3x + 8)/(5x + 8) = 5/7 7(3x + 8) = 5(5x + 8) 21x + 56 = 25x + 40 4x = 16 x = 4 Present age of A = 3x = 3 × 4 = 12 years
Reasoning
If letter positions are summed (A=1…Z=26), TEAM equals:
Sum of positions = 39.
Verbal
Find synonym of "Courageous"
Correct answer: Brave
Quantitative
A sum doubles in 5 years at simple interest. The rate of interest is:
For doubling, RT = 100 → R = 100/5 = 20%.
Reasoning
Which comes next: 5, 10, 20, 40, ?
Each term doubles → 80.
Verbal
The idiom "under the weather" means:
It means: feeling ill.
Quantitative
The LCM of 12 and 18 is:
LCM(12,18) = 36.
Verbal
Identify the error type: "He don't know the answer."
He doesn't / does not - subject-verb agreement.
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Online assessment | Coding and/or MCQ filter | Weekly timed mocks |
| Technical rounds | DSA, CS fundamentals, projects | Live problem solving |
| HR / hiring manager | Motivation and communication | Specific, evidence-based answers |
First round: Intel Online Assessment
Skills emphasized: DSA, computer architecture, OS, C/C++
Languages: C, C++, Python, Verilog (role-dependent)
These are practice-style questions aligned to patterns students report for Intel drives around 2024. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: Eight workers finish a job in 10 days. How many days will 10 workers take for the same job (same pace)?
Solution: Total man-days = 8 × 10 = 80. Days for 10 workers = 80 / 10 = 8 days.
Answer: 8 days
Problem: A vehicle travels at 60 km/h for 2.5 hours. How far does it go?
Solution: Distance = speed × time = 60 × 2.5 = 150 km.
Answer: 150 km
Problem: If two ratios are 3:5 and 5:7, what is the compound ratio?
Solution: Compound ratio = (3/5) × (5/7) = 3/7, written as 3:7.
Answer: 3:7
Problem: Find simple interest on ₹5000 at 8% per annum for 3 years.
Solution: SI = 5000 × 8 × 3 / 100 = ₹1200.
Answer: ₹1200
Problem: A boat’s speed in still water is 15 km/h and the stream is 3 km/h. How long to cover 36 km upstream?
Solution: Upstream speed = 15 − 3 = 12 km/h. Time = 36 / 12 = 3 hours.
Answer: 3 hours
Problem: A mixture has milk and water in the ratio 4:1. If 5 litres of water are added to 20 litres of mixture, what is the new milk:water ratio?
Solution: In 20 L: milk = 16 L, water = 4 L. After adding 5 L water: milk 16, water 9. Ratio = 16:9.
Answer: 16:9
Problem: Find compound interest on ₹10,000 at 10% per annum for 2 years, compounded annually.
Solution: Amount = 10000 × (1.1)² = 10000 × 1.21 = ₹12,100. CI = 12100 − 10000 = ₹2100. (SI for same period would be ₹2000; the extra ₹100 is interest on first-year interest.)
Answer: ₹2100
Problem: What is the angle between the hour and minute hands at 3:00?
Solution: At 3:00 the hands are exactly 90° apart (one quarter of the circle).
Answer: 90°
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Find the first non-repeating character in a string and return its index, or -1 if none exists.
Approach: Count frequencies in one pass (hash map or array of 26 for lowercase). Second pass returns the first index with count 1.
Complexity: O(n) time
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Design a stack that supports push, pop, top, and getMin in average O(1) time.
Approach: Keep a parallel min-stack (or store pairs). When pushing, also push the new minimum. When popping, pop both stacks.
Complexity: O(1) per operation amortized
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array, find the contiguous subarray with the largest sum and return that sum. Example: [-2,1,-3,4,-1,2,1,-5,4] → 6 (from [4,-1,2,1]).
Approach: Keep a running sum. If the running sum drops below 0, reset it to 0 before taking the next element (or track the best ending-here value). Track the global maximum as you scan once from left to right.
Complexity: O(n) time, O(1) extra space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a mutable character array representing a string, reverse it in place without allocating another array of the same size.
Approach: Use two pointers at the start and end. Swap characters, then move inward until the pointers meet. Watch empty and single-character inputs.
Complexity: O(n) time, O(1) extra space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Write a function that returns true if n is prime and false otherwise. Handle n < 2 correctly.
Approach: Return false for n < 2. Trial-divide from 2 to floor(sqrt(n)). If any divisor divides n evenly, it is composite; otherwise prime.
Complexity: O(√n) time
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a string containing only ‘()[]’, decide whether the brackets are balanced and correctly nested.
Approach: Scan left to right with a stack. Push opening brackets. On a closing bracket, the stack top must be the matching opener. At the end the stack must be empty.
Complexity: O(n) time, O(n) space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Intel, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: C, C++, Python, Verilog (role-dependent).
| Area | Why it matters at Intel |
|---|---|
| DSA | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Semiconductor, Computing awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |