Groww 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Groww placement papers from 2025 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Groww patterns and recent shifts.
Groww 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
Groww 2025 coding
DSA practice aligned to Groww online assessments
Groww interview experience
Round structure and tips from student reports
Groww prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
The following table shows the sales of a company over 5 years. Find the average annual growth rate. | Year | Sales (in crores) | |------|-------------------| | 2020 | 100 | | 2021 | 120 | | 2022 | 150 | | 2023 | 180 | | 2024 | 200 |
Correct answer: 19.03%
Verbal
If the cost price of 15 articles is equal to the selling price of 12 articles, find the profit percentage.
Let CP of 1 article = ₹1 CP of 15 articles = ₹15 SP of 12 articles = ₹15 (given) SP of 1 article = ₹15/12 = ₹1.25 Profit = SP - CP = ₹1.25 - ₹1 = ₹0.25 Profit % = (0.25/1) × 100 = 25%
Reasoning
Complete the series: AZ, BY, CX, ?
First letter +1, second −1 → DW.
Reasoning
All roses are flowers. Some flowers fade quickly. Conclusion: All roses fade quickly.
Only some flowers.
Quantitative
The HCF of 36 and 48 is:
36 = 2²×3², 48 = 2⁴×3 → HCF = 2²×3 = 12.
Reasoning
Find the next number: 11, 13, 17, 19, 23, ?
Prime numbers → 29.
Quantitative
A car covers 240 km in 4 hours. What is its average speed?
Correct answer: 60 km/hr
Verbal
Problem: Find the synonym of "ABUNDANT": a) Scarce b) Plentiful c) Limited d) Rare
Abundant means existing in large quantities, so "Plentiful" is the synonym.
Quantitative
Price rises by 25%. By what % should consumption fall to keep expenditure the same?
Reduction = 25/(100+25)×100 = 20%.
Verbal
Fill in: She is good _____ mathematics.
Good at a subject.
Verbal
Synonym of "Abundant":
Abundant means plentiful.
Reasoning
All pens are books. Some books are papers. Conclusion: Some pens are papers.
No definite overlap between pens and papers.
Quantitative
A train 150m long passes a platform 200m long in 14 seconds. Find the speed of the train.
Correct answer: 90 km/hr
Reasoning
Statement: All roses are flowers. Some flowers are red.
From "All roses are flowers" and "Some flowers are red", we cannot conclude that some roses are red (I may not follow) "All red things are flowers" is not necessarily true (II does not follow)
Quantitative
Identify the error: "The data shows that the results are positive."
Correct answer: Subject-verb agreement error
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Online assessment | Coding and/or MCQ filter | Weekly timed mocks |
| Technical rounds | DSA, CS fundamentals, projects | Live problem solving |
| HR / hiring manager | Motivation and communication | Specific, evidence-based answers |
First round: Groww Online Assessment
Skills emphasized: DSA, fintech systems
Languages: Java, Kotlin, Python
These are practice-style questions aligned to patterns students report for Groww drives around 2025. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: Find simple interest on ₹5000 at 8% per annum for 3 years.
Solution: SI = 5000 × 8 × 3 / 100 = ₹1200.
Answer: ₹1200
Problem: A boat’s speed in still water is 15 km/h and the stream is 3 km/h. How long to cover 36 km upstream?
Solution: Upstream speed = 15 − 3 = 12 km/h. Time = 36 / 12 = 3 hours.
Answer: 3 hours
Problem: A mixture has milk and water in the ratio 4:1. If 5 litres of water are added to 20 litres of mixture, what is the new milk:water ratio?
Solution: In 20 L: milk = 16 L, water = 4 L. After adding 5 L water: milk 16, water 9. Ratio = 16:9.
Answer: 16:9
Problem: Find compound interest on ₹10,000 at 10% per annum for 2 years, compounded annually.
Solution: Amount = 10000 × (1.1)² = 10000 × 1.21 = ₹12,100. CI = 12100 − 10000 = ₹2100. (SI for same period would be ₹2000; the extra ₹100 is interest on first-year interest.)
Answer: ₹2100
Problem: What is the angle between the hour and minute hands at 3:00?
Solution: At 3:00 the hands are exactly 90° apart (one quarter of the circle).
Answer: 90°
Problem: In how many ways can 5 different books be arranged on a shelf?
Solution: Arrangements of 5 distinct items = 5! = 120.
Answer: 120
Problem: If the sum of three consecutive integers is 72, what is the smallest of these integers?
Solution: Let the integers be x, x+1, and x+2.
x + (x+1) + (x+2) = 72 3x + 3 = 72 3x = 69 x = 23
So the integers are 23, 24, and 25.
Answer: 23
Problem: A train 150 meters long passes a pole in 15 seconds. What is its speed in km/h?
Solution: Distance = 150 m = 0.15 km. Time = 15 s = 15/3600 h = 1/240 h. Speed = 0.15 ÷ (1/240) = 0.15 × 240 = 36 km/h.
Faster check: 150/15 = 10 m/s → 10 × 18/5 = 36 km/h.
Answer: 36 km/h
Problem: Given a string containing only ‘()[]’, decide whether the brackets are balanced and correctly nested.
Approach: Scan left to right with a stack. Push opening brackets. On a closing bracket, the stack top must be the matching opener. At the end the stack must be empty.
Complexity: O(n) time, O(n) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an array of integers and a target, return indices of two numbers that add up to the target. Assume exactly one solution and you may not use the same element twice.
Approach: Walk the array once. For each value x, check whether target − x was seen earlier in a hash map of value → index. If yes, return both indices; else store x.
Complexity: O(n) time, O(n) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a string s, find the length of the longest substring without repeating characters. Example: ‘abcabcbb’ → 3 (‘abc’).
Approach: Sliding window with a map (or last-seen index) of characters. Expand the right pointer; when a duplicate appears inside the window, move the left pointer past the previous occurrence.
Complexity: O(n) time
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a list of intervals [start, end], merge all overlapping intervals and return the non-overlapping set that covers the same ranges.
Approach: Sort by start time. Walk once, merging into the last interval in the result when the next start is ≤ current end; otherwise append a new interval.
Complexity: O(n log n) time from the sort
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array and an integer k, return the k most frequent elements. Order among equals can be arbitrary unless the problem says otherwise.
Approach: Count frequencies with a hash map, then use a heap of size k (or bucket sort by frequency) to extract the top k keys.
Complexity: O(n log k) with a heap
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the head of a linked list, return true if there is a cycle and false otherwise.
Approach: Floyd’s tortoise and hare: move one pointer one step and another two steps. If they meet, a cycle exists. If the fast pointer hits null, there is no cycle.
Complexity: O(n) time, O(1) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Groww, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, Kotlin, Python.
| Area | Why it matters at Groww |
|---|---|
| DSA | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Investment Platform awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |