Hiring volume
- Total Hires: 600+ freshers expected across India
- Software Engineer L3: 540+ selections
- Product Manager: 35+ selections
- Data Scientist: 25+ selections
- Growth: 20% increase from 2024
This page is a working set of Google placement papers from 2025: from student reports questions, the 2025 online assessment pattern, and step-by-step solutions. Use it to see what Google actually asked in the latest cycle, how hard the rounds were, and which themes (DSA, system design, aptitude, or role-specific topics) mattered most. Practice the problems below under timed conditions, then cross-check with the interview and preparation guides if you are targeting an upcoming Google drive.
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Coding Problem 1 | 1 | 30 min | Medium | Arrays, strings, two pointers |
| Coding Problem 2 | 1 | 30 min | Hard | Trees, graphs, dynamic programming |
| CS Fundamentals MCQs | 18-20 | 30 min | Medium | DSA, time complexity, system design, AI/ML basics |
Total: 20-22 questions, 90 minutes
Key Changes in 2025:
This section contains practice questions styled on Google placement papers 2025 (recent-cycle pattern), with worked solutions. Use them as timed sectional drills - from student reports drives vary by college and role, so treat this as a high-signal practice bank, not an official paper dump.
Problem Statement: Return true if the linked list has a cycle.
Example:
Input: 3→2→0→-4→(back to 2)Output: trueSolution (Java):
public boolean hasCycle(ListNode head) { ListNode slow = head, fast = head; while (fast != null && fast.next != null) { slow = slow.next; fast = fast.next.next; if (slow == fast) return true; } return false;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: You can climb 1 or 2 steps. How many distinct ways to climb n stairs?
Example:
Input: n = 4Output: 5Solution (Java):
public int climbStairs(int n) { if (n <= 2) return n; int a = 1, b = 2; for (int i = 3; i <= n; i++) { int c = a + b; a = b; b = c; } return b;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Return the level-order traversal of a binary tree.
Example:
Input: [3,9,20,null,null,15,7]Output: [[3],[9,20],[15,7]]Solution (Java):
public List<List<Integer>> levelOrder(TreeNode root) { List<List<Integer>> res = new ArrayList<>(); if (root == null) return res; Queue<TreeNode> q = new ArrayDeque<>(); q.add(root); while (!q.isEmpty()) { int sz = q.size(); List<Integer> level = new ArrayList<>(); for (int i = 0; i < sz; i++) { TreeNode n = q.poll(); level.add(n.val); if (n.left != null) q.add(n.left); if (n.right != null) q.add(n.right); } res.add(level); } return res;}Time Complexity: O(n)
Space Complexity: O(n)
Problem Statement: Rotate the array to the right by k steps.
Example:
Input: [1,2,3,4,5,6,7], k = 3Output: [5,6,7,1,2,3,4]Solution (Java):
public void rotate(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1);}void reverse(int[] a, int l, int r) { while (l < r) { int t = a[l]; a[l++] = a[r]; a[r--] = t; }}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Return the first non-repeating character in a string, or ‘_’ if none.
Example:
Input: "swiss"Output: 'w'Solution (Java):
public char firstUnique(String s) { int[] freq = new int[256]; for (char c : s.toCharArray()) freq[c]++; for (char c : s.toCharArray()) if (freq[c] == 1) return c; return '_';}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Given a string of brackets, determine if it is valid.
Example:
Input: "()[]{}"Output: trueSolution (Java):
public boolean isValid(String s) { Deque<Character> st = new ArrayDeque<>(); Map<Character, Character> pair = Map.of(')', '(', ']', '[', '}', '{'); for (char c : s.toCharArray()) { if (pair.containsValue(c)) st.push(c); else if (st.isEmpty() || st.pop() != pair.get(c)) return false; } return st.isEmpty();}Time Complexity: O(n)
Space Complexity: O(n)
Problem Statement: Given a string, return it reversed.
Example:
Input: "placement"Output: "tnemecalp"Solution (Java):
public String reverse(String s) { return new StringBuilder(s).reverse().toString();}Time Complexity: O(n)
Space Complexity: O(n)
Solution:
HAVING filters aggregates; WHERE filters rows before grouping.
Answer: HAVING
Solution:
Each step halves the search space → O(log n).
Answer: O(log n)
Solution:
FIFO = First In First Out → Queue. Stack is LIFO.
Answer: Queue
Solution:
TCP is connection-oriented; UDP is connectionless.
Answer: TCP
Hiring volume
Salary packages
New initiatives
Coding Problems:
New Focus Areas:
Based on recent candidate experiences from 2025 Google interviews:
2025 Interview Process:
2025 Interview Trends:
Common 2025 Interview Topics:
2025 Interview Questions Examples:
Success Tips:
Difficulty Rating: 3.4-3.5/5 (Most challenging among FAANG)
For detailed interview experiences from 2025, visit Google Interview Experience page.
Google 2025 paper 1
Latest 2025 online assessment with coding problems and MCQs
Google 2025 paper 2
Additional 2025 questions with detailed solutions
2025 coding examples
Collection of 2025 coding problems with solutions