Genpact 2026 Pattern Details

Overview

Use this page to prepare for Genpact placement drives in 2026. It outlines the expected online assessment and interview shape based on recent Genpact hiring cycles, the topics that keep showing up (coding/DSA, core CS, and role-specific rounds), and a practical multi-month study plan. Pair it with the 2024 and 2025 papers on this site so you are drilling current-style questions while tracking what may change next year.

Genpact Online Assessment 2026 expected pattern

Section	Questions	Time	Difficulty	Focus Areas
Aptitude	15-18	45 min	Medium	Quantitative, Logical Reasoning, Verbal
Technical	5-7	20 min	Medium	Programming, Data Structures, DBMS
Coding	1-2	25 min	Medium-Hard	Array, String, Basic Algorithms

Total: 25-30 questions, 90 minutes
Platform: Genpact assessment platform
Languages Allowed: C, C++, Java, Python
Expected Success Rate: ~25-30% cleared OA and advanced to interviews

Genpact Placement Papers 2026 - expected questions & solutions

This section contains expected question types for Genpact placement papers 2026 based on previous year patterns and industry trends.

Question 1: simple interest

Q1: A sum of money amounts to ₹10,500 after 3 years and ₹12,000 after 5 years at the same rate of simple interest. Find the rate of interest per annum.

Solution:

Let Principal = P, Rate = R%

After 3 years: P + (P × R × 3)/100 = 10,500 After 5 years: P + (P × R × 5)/100 = 12,000

Subtracting: (P × R × 2)/100 = 12,000 - 10,500 = 1,500

P × R = 75,000

From first equation: P + (75,000 × 3)/100 = 10,500 P + 2,250 = 10,500 P = 8,250

Rate R = 75,000/8,250 = 9.09% per annum (approximately 9%)

Answer: 9% per annum

Question 2: profit and loss

Q2: A trader sells an article at a profit of 25%. If he had bought it at 10% less and sold it for ₹15 less, he would have gained 30%. Find the cost price of the article.

Solution:

Let actual CP = x Actual SP = 1.25x (25% profit)

New CP = 0.9x (10% less) New SP = 1.25x - 15 New Profit = (1.25x - 15) - 0.9x = 0.35x - 15 New Profit % = ((0.35x - 15)/0.9x) × 100 = 30

(0.35x - 15)/0.9x = 0.30 0.35x - 15 = 0.27x 0.08x = 15 x = ₹187.50

Answer: ₹187.50

Question 3: time and work

Q3: A can complete a work in 20 days, B in 30 days. They work together for 6 days, then A leaves. How long will B take to complete the remaining work?

Solution:

Let the total work be LCM of 20 and 30 = 60 units.

A’s rate = 60/20 = 3 units/day
B’s rate = 60/30 = 2 units/day
Combined rate = 3 + 2 = 5 units/day

Work done in 6 days = 6 × 5 = 30 units Remaining work = 60 - 30 = 30 units

Time for B to complete remaining = 30/2 = 15 days

Answer: 15 days

Question 4: mixtures and alligations

Q4: A mixture contains milk and water in the ratio 4:1. If 5 liters of water is added, the ratio becomes 4:2. Find the quantity of milk in the mixture.

Solution:

Let milk = 4x, water = x

After adding 5 liters water: Milk = 4x, Water = x + 5

Ratio: 4x/(x + 5) = 4/2 = 2/1 4x = 2(x + 5) 4x = 2x + 10 2x = 10 x = 5

Quantity of milk = 4x = 4 × 5 = 20 liters

Answer: 20 liters

Question 5: syllogism

Q5: Statements: All engineers are professionals. Some professionals are managers. Conclusions: I. Some engineers are managers. II. All managers are engineers.

Solution:

Analyzing the statements:

All engineers are professionals (A → B)
Some professionals are managers (B → C, some)

Conclusion I: Some engineers are managers

Since all engineers are professionals, and some professionals are managers, we can say some engineers are managers. Valid

Conclusion II: All managers are engineers

This cannot be concluded from the given statements. Invalid

Answer: Only conclusion I follows

Question 6: data sufficiency

Q6: What is the value of x? Statement I: x² - 6x + 8 = 0. Statement II: x < 5.

Solution:

Statement I: x² - 6x + 8 = 0 (x - 2)(x - 4) = 0 x = 2 or x = 4

Statement II: x < 5 (both 2 and 4 satisfy this)

Combining both: x = 2 or x = 4 (both < 5)

Answer: Both statements together are not sufficient to determine unique value of x

Question 7: array manipulation

Q7: Find the maximum sum of a contiguous subarray (Kadane’s Algorithm).

Problem Statement: Given an array of integers, find the maximum sum of a contiguous subarray.

Example:

Input: nums = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
Output: 6 (subarray [4, -1, 2, 1])

Solution (Java):

public int maxSubArray(int[] nums) {
    int maxSum = nums[0];
    int currentSum = nums[0];

    for (int i = 1; i < nums.length; i++) {
        currentSum = Math.max(nums[i], currentSum + nums[i]);
        maxSum = Math.max(maxSum, currentSum);
    }

    return maxSum;
}

Time Complexity: O(n)
Space Complexity: O(1)

Question 8: string processing

Q8: Reverse words in a string.

Problem Statement: Given a string, reverse the order of words.

Example:

Input: "the sky is blue"
Output: "blue is sky the"

Solution (Java):

public String reverseWords(String s) {
    String[] words = s.trim().split("\\s+");
    StringBuilder result = new StringBuilder();

    for (int i = words.length - 1; i >= 0; i--) {
        result.append(words[i]);
        if (i > 0) result.append(" ");
    }

    return result.toString();
}

Time Complexity: O(n)
Space Complexity: O(n)

Question 9: two sum

Q9: Find two numbers that add up to a target value.

Problem Statement: Given an array of integers and a target sum, find two numbers that add up to the target.

Example:

Input: nums = [2, 7, 11, 15], target = 9
Output: [0, 1] (indices of 2 and 7)

Solution (Java):

public int[] twoSum(int[] nums, int target) {
    Map<Integer, Integer> map = new HashMap<>();

    for (int i = 0; i < nums.length; i++) {
        int complement = target - nums[i];
        if (map.containsKey(complement)) {
            return new int[]{map.get(complement), i};
        }
        map.put(nums[i], i);
    }

    return new int[]{};
}

Time Complexity: O(n)
Space Complexity: O(n)

2026 expected hiring trends

Expected hiring

Total Hires: 6000+ freshers (expected)
Process Associate: 5400+ selections (expected)
Associate: 450+ selections (expected)
Locations: Pan-India

Expected salary packages

Process Associate: ₹3.5-4.5 LPA
Associate: ₹6-7 LPA
Software Engineer: ₹8-10 LPA

Expected question trends

Aptitude: Medium (60% of questions)
Technical: Medium (25% of questions)
Coding: Medium-Hard (15% of questions)
Focus: Fundamentals and problem-solving

Key insights for 2026 preparation

Aptitude Focus: Expected continued emphasis on quantitative ability and logical reasoning
Time Management: 90 minutes for 25-30 questions requires good speed and accuracy
Coding Basics: Focus on fundamental problems (arrays, strings, basic algorithms)
Technical Concepts: DBMS, OOPs, and programming fundamentals remain important
Problem-Solving: Emphasis on clear approach and correct implementation
Preparation: Practice with 2024 and 2025 papers to understand patterns

Preparation strategy for 2026

Recommended Preparation Steps:

Review Previous Year Papers: Practice Genpact placement papers 2024 and 2025
Aptitude Practice: Focus on quantitative aptitude and logical reasoning
Coding Practice: Solve array, string, and basic algorithm problems
Technical Review: Revise DBMS, OOPs, and programming fundamentals
Mock Tests: Take timed practice tests to improve speed and accuracy

Comments & Suggestions

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Genpact 2026 Pattern Details

Overview

Genpact Online Assessment 2026 expected pattern

Genpact Placement Papers 2026 - expected questions & solutions

Question 1: simple interest

Question 2: profit and loss

Question 3: time and work

Question 4: mixtures and alligations

Question 5: syllogism

Question 6: data sufficiency

Question 7: array manipulation

Question 8: string processing

Question 9: two sum

2026 expected hiring trends

Key insights for 2026 preparation

Preparation strategy for 2026

Comments & Suggestions

Related resources

Similar companies