Dell 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Dell placement papers from 2025 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Dell patterns and recent shifts.
Dell 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
Dell 2025 coding
DSA practice aligned to Dell online assessments
Dell interview experience
Round structure and tips from student reports
Dell prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Reasoning
If letter positions are summed (A=1…Z=26), ART equals:
Sum of positions = 39.
Quantitative
If the sum of three consecutive integers is 72, what is the smallest of these integers?
Let the integers be x, x+1, and x+2. x + (x + 1) + (x + 2) = 72 3x + 3 = 72 3x = 69 x = 23 Therefore, the integers are 23, 24, and 25.
Reasoning
Find the missing number: 5, 11, 23, 47, 95, ?
Correct answer: 191
Reasoning
What is the interest rate? Statement I: The interest on ₹10,000 for 1 year is ₹800. Statement II: The interest rate is less than 10%.
Statement I: Interest = ₹800, Principal = ₹10,000, Time = 1 year Rate = (Interest × 100) / (Principal × Time) = (800 × 100) / (10,000 × 1) = 8% Statement II: Rate < 10% (doesn't give exact value)
Verbal
There are two pipes in a tank. Pipe A is for filling the tank and pipe B is for emptying the tank. If A can fill the tank in 10 hours and B can empty the tank in 15 hours then find how many hours will it take to completely fill a half empty tank?
Correct answer: 15 hours
Quantitative
If 20% of a number is 48, the number is:
Number = 48 × 100/20 = 240.
Verbal
A bouquet of flowers _____ on the table.
Bouquet is singular.
Reasoning
Arrange the words: 1. Elephant 2. Cat 3. Dog 4. Ant
Correct answer: 4, 2, 3, 1
Quantitative
A person covers a certain distance at a speed of 50 km/h and returns at 30 km/h. What is the average speed for the entire journey?
Let distance = D km Time forward = D/50 hours Time return = D/30 hours Total time = D/50 + D/30 = D(3+5)/150 = 8D/150 = 4D/75 hours Total distance = 2D km Average speed = 2D / (4D/75) = 2D × 75/4D = 37.5 km/h
Verbal
Neither the teacher nor the students _____ present.
Verb agrees with nearer subject (students) → were.
Reasoning
Arrange in dictionary order: Apple, Apply, Apt, Apex. Third word is:
Order: Apex, Apple, Apply, Apt → third is Apply.
Quantitative
If "CAT" is coded as "3120", how is "DOG" coded? (A=1, B=2, C=3...)
Correct answer: 4157
Quantitative
The present age of father is 3 times the age of his son. After 5 years, the father's age will be 2.5 times the son's age. Find the present age of son.
Correct answer: 15 years
Quantitative
Find the simple interest on ₹5000 for 3 years at 8% per annum.
Correct answer: ₹1200
Verbal
Antonym of "Benevolent":
Benevolent ↔ malevolent.
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Online assessment | Coding and/or MCQ filter | Weekly timed mocks |
| Technical rounds | DSA, CS fundamentals, projects | Live problem solving |
| HR / hiring manager | Motivation and communication | Specific, evidence-based answers |
First round: Dell Online Assessment
Skills emphasized: Aptitude, coding, CS fundamentals
Languages: Java, C, C++, Python
These are practice-style questions aligned to patterns students report for Dell drives around 2025. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: A number is increased by 20% and then decreased by 20%. What is the net percentage change?
Solution: Start with 100 → 120 → 96. Net change = 4% decrease. Formula: successive +a then −a gives −(a²/100)% = −4%.
Answer: 4% decrease
Problem: If the price of an item rises by 25%, by what percent should consumption fall so that expenditure stays the same?
Solution: Required reduction = r/(100+r) × 100 with r = 25. = 25/125 × 100 = 20%.
Answer: 20%
Problem: An article is marked 40% above cost and sold after a 10% discount. Find the profit percent.
Solution: SP = CP × 1.4 × 0.9 = 1.26 CP. Profit = 26%.
Answer: 26%
Problem: An article sold at 10% loss would give 5% profit if sold for ₹60 more. Find the cost price.
Solution: 0.9P + 60 = 1.05P 60 = 0.15P P = 60 / 0.15 = ₹400.
Answer: ₹400
Problem: Eight workers finish a job in 10 days. How many days will 10 workers take for the same job (same pace)?
Solution: Total man-days = 8 × 10 = 80. Days for 10 workers = 80 / 10 = 8 days.
Answer: 8 days
Problem: A vehicle travels at 60 km/h for 2.5 hours. How far does it go?
Solution: Distance = speed × time = 60 × 2.5 = 150 km.
Answer: 150 km
Problem: If two ratios are 3:5 and 5:7, what is the compound ratio?
Solution: Compound ratio = (3/5) × (5/7) = 3/7, written as 3:7.
Answer: 3:7
Problem: Find simple interest on ₹5000 at 8% per annum for 3 years.
Solution: SI = 5000 × 8 × 3 / 100 = ₹1200.
Answer: ₹1200
Problem: Given a string containing only ‘()[]’, decide whether the brackets are balanced and correctly nested.
Approach: Scan left to right with a stack. Push opening brackets. On a closing bracket, the stack top must be the matching opener. At the end the stack must be empty.
Complexity: O(n) time, O(n) space
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an array of integers and a target, return indices of two numbers that add up to the target. Assume exactly one solution and you may not use the same element twice.
Approach: Walk the array once. For each value x, check whether target − x was seen earlier in a hash map of value → index. If yes, return both indices; else store x.
Complexity: O(n) time, O(n) space
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a string s, find the length of the longest substring without repeating characters. Example: ‘abcabcbb’ → 3 (‘abc’).
Approach: Sliding window with a map (or last-seen index) of characters. Expand the right pointer; when a duplicate appears inside the window, move the left pointer past the previous occurrence.
Complexity: O(n) time
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a list of intervals [start, end], merge all overlapping intervals and return the non-overlapping set that covers the same ranges.
Approach: Sort by start time. Walk once, merging into the last interval in the result when the next start is ≤ current end; otherwise append a new interval.
Complexity: O(n log n) time from the sort
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array and an integer k, return the k most frequent elements. Order among equals can be arbitrary unless the problem says otherwise.
Approach: Count frequencies with a hash map, then use a heap of size k (or bucket sort by frequency) to extract the top k keys.
Complexity: O(n log k) with a heap
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the head of a linked list, return true if there is a cycle and false otherwise.
Approach: Floyd’s tortoise and hare: move one pointer one step and another two steps. If they meet, a cycle exists. If the fast pointer hits null, there is no cycle.
Complexity: O(n) time, O(1) space
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Dell tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Dell, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, C, C++, Python.
| Area | Why it matters at Dell |
|---|---|
| Aptitude | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Enterprise Hardware & IT awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |