Synopsys 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Synopsys placement papers from 2025 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Synopsys patterns and recent shifts.
Synopsys 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
Synopsys 2025 coding
DSA practice aligned to Synopsys online assessments
Synopsys interview experience
Round structure and tips from student reports
Synopsys prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
A student scored 60, 70, and 80 in three subjects. If the weights are 2, 3, and 5 respectively, find the weighted average.
Correct answer: 73
Reasoning
Find the missing number: 5, 11, 23, 47, 95, ?
Correct answer: 191
Quantitative
A sum doubles in 5 years at simple interest. The rate of interest is:
For doubling, RT = 100 → R = 100/5 = 20%.
Reasoning
A walks 9 km north, then 12 km east. Distance from start is:
Right triangle → 15 km.
Quantitative
Find the remainder when 2^31 is divided by 5.
Pattern of 2^n mod 5: 2^1=2, 2^2=4, 2^3=3, 2^4=1, 2^5=2 (cycle repeats every 4) 31 mod 4 = 3 So 2^31 mod 5 = 2^3 mod 5 = 3
Quantitative
A number is increased by 25% and then decreased by 25%. Find the net percentage change.
Let original number = 100 After 25% increase: 100 + 25 = 125 After 25% decrease: 125 - (25% of 125) = 125 - 31.25 = 93.75 Net change = 100 - 93.75 = 6.25 Net percentage change = (6.25/100) × 100 = 6.25% decrease
Verbal
Choose the correctly spelled word:
Correct spelling is Accommodation.
Reasoning
If every letter is shifted +2 in the alphabet, BOOK becomes:
Each letter +2 → DQQM.
Reasoning
Statements: All cats are animals. Some animals are dogs. Conclusions: I. Some cats are dogs. II. All dogs are cats.
Analyzing the statements: - All cats are animals (A → B) - Some animals are dogs (B → C, some) Conclusion I: Some cats are dogs - Cannot be concluded. Some animals are dogs, but cats are a subset of animals. We cannot say some cats are dogs. Invalid Conclusion
Reasoning
Find the next number: 8, 6, 9, 7, 10, ?
−2,+3 alternating → 10-2=8 → 8.
Verbal
Synonym of "Abundant":
Abundant means plentiful.
Verbal
The idiom "under the weather" means:
It means: feeling ill.
Quantitative
Price rises by 25%. By what % should consumption fall to keep expenditure the same?
Reduction = 25/(100+25)×100 = 20%.
Quantitative
The LCM of 12 and 18 is:
LCM(12,18) = 36.
Verbal
Each of the boys _____ given a prize.
"Each" takes singular verb → was.
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Online assessment | Coding and/or MCQ filter | Weekly timed mocks |
| Technical rounds | DSA, CS fundamentals, projects | Live problem solving |
| HR / hiring manager | Motivation and communication | Specific, evidence-based answers |
First round: Synopsys Online Test
Skills emphasized: DSA, digital design basics, C++/Python
Languages: C++, Python, SystemVerilog (role-dependent)
These are practice-style questions aligned to patterns students report for Synopsys drives around 2025. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: If the price of an item rises by 25%, by what percent should consumption fall so that expenditure stays the same?
Solution: Required reduction = r/(100+r) × 100 with r = 25. = 25/125 × 100 = 20%.
Answer: 20%
Problem: An article is marked 40% above cost and sold after a 10% discount. Find the profit percent.
Solution: SP = CP × 1.4 × 0.9 = 1.26 CP. Profit = 26%.
Answer: 26%
Problem: An article sold at 10% loss would give 5% profit if sold for ₹60 more. Find the cost price.
Solution: 0.9P + 60 = 1.05P 60 = 0.15P P = 60 / 0.15 = ₹400.
Answer: ₹400
Problem: Eight workers finish a job in 10 days. How many days will 10 workers take for the same job (same pace)?
Solution: Total man-days = 8 × 10 = 80. Days for 10 workers = 80 / 10 = 8 days.
Answer: 8 days
Problem: A vehicle travels at 60 km/h for 2.5 hours. How far does it go?
Solution: Distance = speed × time = 60 × 2.5 = 150 km.
Answer: 150 km
Problem: If two ratios are 3:5 and 5:7, what is the compound ratio?
Solution: Compound ratio = (3/5) × (5/7) = 3/7, written as 3:7.
Answer: 3:7
Problem: Find simple interest on ₹5000 at 8% per annum for 3 years.
Solution: SI = 5000 × 8 × 3 / 100 = ₹1200.
Answer: ₹1200
Problem: A boat’s speed in still water is 15 km/h and the stream is 3 km/h. How long to cover 36 km upstream?
Solution: Upstream speed = 15 − 3 = 12 km/h. Time = 36 / 12 = 3 hours.
Answer: 3 hours
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Find the first non-repeating character in a string and return its index, or -1 if none exists.
Approach: Count frequencies in one pass (hash map or array of 26 for lowercase). Second pass returns the first index with count 1.
Complexity: O(n) time
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Design a stack that supports push, pop, top, and getMin in average O(1) time.
Approach: Keep a parallel min-stack (or store pairs). When pushing, also push the new minimum. When popping, pop both stacks.
Complexity: O(1) per operation amortized
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array, find the contiguous subarray with the largest sum and return that sum. Example: [-2,1,-3,4,-1,2,1,-5,4] → 6 (from [4,-1,2,1]).
Approach: Keep a running sum. If the running sum drops below 0, reset it to 0 before taking the next element (or track the best ending-here value). Track the global maximum as you scan once from left to right.
Complexity: O(n) time, O(1) extra space
Synopsys tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Synopsys, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: C++, Python, SystemVerilog (role-dependent).
| Area | Why it matters at Synopsys |
|---|---|
| DSA | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| EDA, Semiconductor IP awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |
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