Persistent Systems 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
Persistent Systems 2026 Pattern Details
Overview
This page collects Persistent Systems placement papers from 2026 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Persistent Systems patterns and recent shifts.
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Persistent Systems 2026 coding
DSA practice aligned to Persistent Systems online assessments
Persistent Systems interview experience
Round structure and tips from student reports
Persistent Systems prep guide
Study plan and weekly schedule
Persistent Systems Aptitude Mock Quiz
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Questions15
Time10 min
Reasoning
All pens are books. Some books are papers. Conclusion: Some pens are papers.
No definite overlap between pens and papers.
Reasoning
In how many ways can 4 books be arranged on a shelf?
Correct answer: 24 ways
Quantitative
Compound interest on ₹1000 at 10% for 2 years (annual compounding):
1000×1.1² − 1000 = 210.
Verbal
Problem: "She is allergic _____ peanuts." a) to b) from c) with d) by
"Allergic to" is the correct prepositional phrase.
Quantitative
Pointing to a photograph, a man says, "She is the daughter of my grandfather's only son." How is the girl related to the man?
The man's grandfather's only son = the man's father Daughter of the man's father = the man's sister Therefore, the girl is the man's sister.
Quantitative
If cost price is ₹250 and profit is 20%, selling price is:
SP = 250 × 1.2 = ₹300.
Reasoning
How many 9s are there between 1 and 100?
9,19,29,39,49,59,69,79,89,90-99 → 20 nines.
Verbal
"Break the ice" means:
It means to initiate conversation in a social setting.
Quantitative
The average of 5 numbers is 20. If one number is removed, the average becomes 18. Find the removed number.
Correct answer: 28
Quantitative
A number is increased by 20% and then decreased by 20%. Find the net percentage change.
Let original = 100 After 20% increase: 120 After 20% decrease: 96 Net change = 4% decrease
Verbal
Choose the correctly spelled word:
Correct spelling is Accommodation.
Reasoning
Series: 1, 4, 9, 16, 25, ?
Perfect squares → 36.
Reasoning
Statements: 1. Some books are novels, 2. All novels are stories, 3. No story is a poem
From 1 and 2: Some books are stories (I follows) From 2 and 3: No novel is a poem (II follows) From I: Some stories are books (III follows)
Verbal
"To add fuel to the fire" means:
It means worsening a conflict or situation.
Quantitative
A and B finish a job in 12 and 18 days. Working together they finish in:
1/12 + 1/18 = 5/36 → 36/5 = 7.2 days.
Your score
0/15(0%)
Review
Persistent Systems exam pattern 2026
| Section | What shows up | Prep focus |
|---|---|---|
| Aptitude / logical | Quant, reasoning, sometimes verbal | Timed sectional accuracy |
| Coding / programming logic | Easy-medium DSA or output-style MCQs | Handle tricky inputs |
| Technical interview | OOPs, DBMS, OS, projects | Explain aloud |
| HR | Fit, location, intent | A few real examples ready |
First round: Persistent Online Assessment
Skills emphasized: Coding, OOPs, DBMS, aptitude
Languages: Java, C++, Python
Sample Persistent Systems questions with solutions
These are practice-style questions aligned to patterns students report for Persistent Systems drives around 2026. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Quantitative aptitude (2026)
Q1: CI vs SI hint
Problem: Find compound interest on ₹10,000 at 10% per annum for 2 years, compounded annually.
Solution: Amount = 10000 × (1.1)² = 10000 × 1.21 = ₹12,100. CI = 12100 − 10000 = ₹2100. (SI for same period would be ₹2000; the extra ₹100 is interest on first-year interest.)
Answer: ₹2100
Q2: Clock angle
Problem: What is the angle between the hour and minute hands at 3:00?
Solution: At 3:00 the hands are exactly 90° apart (one quarter of the circle).
Answer: 90°
Q3: Permutation basic
Problem: In how many ways can 5 different books be arranged on a shelf?
Solution: Arrangements of 5 distinct items = 5! = 120.
Answer: 120
Q4: Consecutive integers
Problem: If the sum of three consecutive integers is 72, what is the smallest of these integers?
Solution: Let the integers be x, x+1, and x+2.
x + (x+1) + (x+2) = 72 3x + 3 = 72 3x = 69 x = 23
So the integers are 23, 24, and 25.
Answer: 23
Q5: Train and pole
Problem: A train 150 meters long passes a pole in 15 seconds. What is its speed in km/h?
Solution: Distance = 150 m = 0.15 km. Time = 15 s = 15/3600 h = 1/240 h. Speed = 0.15 ÷ (1/240) = 0.15 × 240 = 36 km/h.
Faster check: 150/15 = 10 m/s → 10 × 18/5 = 36 km/h.
Answer: 36 km/h
Q6: Profit on a pen
Problem: If the cost price of a pen is ₹40 and it is sold at a 25% profit, what is the selling price?
Solution: Profit = 25% of 40 = ₹10. Selling price = 40 + 10 = ₹50.
Or SP = CP × 1.25 = 40 × 1.25 = ₹50.
Answer: ₹50
Q7: A and B together
Problem: A can finish a job in 10 days and B in 20 days. How long will they take working together?
Solution: A’s one-day work = 1/10. B’s one-day work = 1/20. Together = 1/10 + 1/20 = 3/20 per day. Time = 20/3 ≈ 6.67 days (6 days 16 hours).
Answer: 20/3 days
Q8: Sum of naturals
Problem: What is the sum of the first 50 natural numbers?
Solution: Sum of first n naturals = n(n+1)/2. For n = 50: 50 × 51 / 2 = 1275.
Answer: 1275
Logical reasoning (2026)
Q1: Coding letter shift
Problem: If CAT is coded as DBU, how is DOG coded in the same way?
Solution: Each letter moves +1 in the alphabet: C→D, A→B, T→U. D→E, O→P, G→H → EPH.
Answer: EPH
Q2: Blood relation
Problem: Pointing to a photograph, Ravi says, ‘She is the daughter of my mother’s only son.’ How is the girl related to Ravi?
Solution: Ravi’s mother’s only son is Ravi himself (assuming one son). The girl is therefore Ravi’s daughter.
Answer: Daughter
Q3: Syllogism
Problem: Statements: All engineers are graduates. Some graduates are managers. Conclusion: Some engineers are managers. Does it follow?
Solution: The ‘some graduates’ who are managers need not overlap with the engineers. The conclusion does not follow necessarily.
Answer: Does not follow
Q4: Direction turn
Problem: A person walks 5 km north, then 3 km east, then 5 km south. How far is he from the start, and in which direction?
Solution: North 5 and south 5 cancel. He is 3 km east of the start.
Answer: 3 km east
Coding practice (2026)
Coding Q1: Longest substring without repeating characters
Problem: Given a string s, find the length of the longest substring without repeating characters. Example: ‘abcabcbb’ → 3 (‘abc’).
Approach: Sliding window with a map (or last-seen index) of characters. Expand the right pointer; when a duplicate appears inside the window, move the left pointer past the previous occurrence.
Complexity: O(n) time
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q2: Merge overlapping intervals
Problem: Given a list of intervals [start, end], merge all overlapping intervals and return the non-overlapping set that covers the same ranges.
Approach: Sort by start time. Walk once, merging into the last interval in the result when the next start is ≤ current end; otherwise append a new interval.
Complexity: O(n log n) time from the sort
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q3: Top K frequent elements
Problem: Given an integer array and an integer k, return the k most frequent elements. Order among equals can be arbitrary unless the problem says otherwise.
Approach: Count frequencies with a hash map, then use a heap of size k (or bucket sort by frequency) to extract the top k keys.
Complexity: O(n log k) with a heap
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q4: Linked list cycle
Problem: Given the head of a linked list, return true if there is a cycle and false otherwise.
Approach: Floyd’s tortoise and hare: move one pointer one step and another two steps. If they meet, a cycle exists. If the fast pointer hits null, there is no cycle.
Complexity: O(n) time, O(1) space
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q5: Binary tree level order
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q6: Coin change (min coins)
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q7: Binary search
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Coding Q8: Move zeros
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Persistent Systems tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Deep prep notes for Persistent Systems
How the persistent Online Assessment usually feels
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Persistent Systems, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, C++, Python.
Topic weight hints
| Area | Why it matters at Persistent Systems |
|---|---|
| Coding | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Software Product Engineering awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |
14-Day sprint
- Days 1-3: Learn the 2026 pattern and take two sectional mocks
- Days 4-7: Closed practice on weak topics from your error log
- Days 8-10: Full mocks every other day; review the same day
- Days 11-14: Practice explaining projects out loud, light revision, sleep and IDs ready
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