Intel 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Intel placement papers from 2026 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Intel patterns and recent shifts.
Intel 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
Intel 2026 coding
DSA practice aligned to Intel online assessments
Intel interview experience
Round structure and tips from student reports
Intel prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Reasoning
All cats are animals. Some animals are dogs. Therefore, some cats are dogs. Is the conclusion valid?
The conclusion is invalid. While all cats are animals and some animals are dogs, there is no information linking cats directly to dogs. The conclusion cannot be logically derived from the given statements.
Quantitative
If 3x + 5 = 20, then x equals:
3x = 15 → x = 5.
Quantitative
A bank offers a loan of ₹50,000 at 8% per annum simple interest. What is the interest after 2 years?
Correct answer: ₹8,000
Reasoning
Odd one out: Triangle, Square, Circle, Rectangle
Circle has no straight sides.
Verbal
Synonym of "Crucial":
Crucial means important.
Reasoning
Complete the series: AZ, BY, CX, ?
First letter +1, second −1 → DW.
Quantitative
If a number is increased by 20% and then decreased by 15%, what is the net change?
Correct answer: +2% increase
Quantitative
The ratio of ages of A and B is 3:5. After 8 years, the ratio becomes 5:7. Find the present age of A.
Let present ages be 3x and 5x. After 8 years: - A's age: 3x + 8 - B's age: 5x + 8 Given: (3x + 8)/(5x + 8) = 5/7 7(3x + 8) = 5(5x + 8) 21x + 56 = 25x + 40 4x = 16 x = 4 Present age of A = 3x = 3 × 4 = 12 years
Reasoning
If letter positions are summed (A=1…Z=26), TEAM equals:
Sum of positions = 39.
Verbal
Find synonym of "Courageous"
Correct answer: Brave
Quantitative
A sum doubles in 5 years at simple interest. The rate of interest is:
For doubling, RT = 100 → R = 100/5 = 20%.
Reasoning
Which comes next: 5, 10, 20, 40, ?
Each term doubles → 80.
Verbal
The idiom "under the weather" means:
It means: feeling ill.
Quantitative
The LCM of 12 and 18 is:
LCM(12,18) = 36.
Verbal
Identify the error type: "He don't know the answer."
He doesn't / does not - subject-verb agreement.
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Online assessment | Coding and/or MCQ filter | Weekly timed mocks |
| Technical rounds | DSA, CS fundamentals, projects | Live problem solving |
| HR / hiring manager | Motivation and communication | Specific, evidence-based answers |
First round: Intel Online Assessment
Skills emphasized: DSA, computer architecture, OS, C/C++
Languages: C, C++, Python, Verilog (role-dependent)
These are practice-style questions aligned to patterns students report for Intel drives around 2026. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: What is the sum of the first 50 natural numbers?
Solution: Sum of first n naturals = n(n+1)/2. For n = 50: 50 × 51 / 2 = 1275.
Answer: 1275
Problem: A person covers a distance at 60 km/h and returns at 40 km/h. What is the average speed for the whole trip?
Solution: For equal distances, average speed = 2ab/(a+b). = 2×60×40 / (60+40) = 4800/100 = 48 km/h.
Do not take the arithmetic mean (50); that would be wrong here.
Answer: 48 km/h
Problem: A shopkeeper marks goods 20% above cost and then gives a 10% discount. What is the profit percentage?
Solution: Let CP = ₹100. Marked price = ₹120. Discount = 10% of 120 = ₹12. SP = 120 − 12 = ₹108. Profit % = 8%.
Answer: 8%
Problem: A finishes work in 12 days, B in 15 days, and C in 20 days. Working together, how many days do they need?
Solution: Take total work = LCM(12,15,20) = 60 units. A = 5/day, B = 4/day, C = 3/day. Combined = 12 units/day. Time = 60/12 = 5 days.
Answer: 5 days
Problem: The ratio of ages of A and B is 3:5. After 8 years the ratio becomes 5:7. Find A’s present age.
Solution: Let ages be 3x and 5x. (3x+8)/(5x+8) = 5/7 7(3x+8) = 5(5x+8) 21x + 56 = 25x + 40 4x = 16 → x = 4 A’s age = 12 years.
Answer: 12 years
Problem: Pipe A fills a tank in 6 hours and pipe B in 8 hours. How long do they take together to fill it?
Solution: Combined rate = 1/6 + 1/8 = 4/24 + 3/24 = 7/24. Time = 24/7 hours ≈ 3 hours 26 minutes.
Answer: 24/7 hours
Problem: Find the simple interest on ₹8000 at 10% per annum for 2 years.
Solution: SI = (P × R × T) / 100 = (8000 × 10 × 2) / 100 = ₹1600.
Answer: ₹1600
Problem: If 30% of a number is 150, what is the number?
Solution: 0.3x = 150 → x = 150 / 0.3 = 500.
Answer: 500
Problem: Given an array of integers and a target, return indices of two numbers that add up to the target. Assume exactly one solution and you may not use the same element twice.
Approach: Walk the array once. For each value x, check whether target − x was seen earlier in a hash map of value → index. If yes, return both indices; else store x.
Complexity: O(n) time, O(n) space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a string s, find the length of the longest substring without repeating characters. Example: ‘abcabcbb’ → 3 (‘abc’).
Approach: Sliding window with a map (or last-seen index) of characters. Expand the right pointer; when a duplicate appears inside the window, move the left pointer past the previous occurrence.
Complexity: O(n) time
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a list of intervals [start, end], merge all overlapping intervals and return the non-overlapping set that covers the same ranges.
Approach: Sort by start time. Walk once, merging into the last interval in the result when the next start is ≤ current end; otherwise append a new interval.
Complexity: O(n log n) time from the sort
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array and an integer k, return the k most frequent elements. Order among equals can be arbitrary unless the problem says otherwise.
Approach: Count frequencies with a hash map, then use a heap of size k (or bucket sort by frequency) to extract the top k keys.
Complexity: O(n log k) with a heap
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the head of a linked list, return true if there is a cycle and false otherwise.
Approach: Floyd’s tortoise and hare: move one pointer one step and another two steps. If they meet, a cycle exists. If the fast pointer hits null, there is no cycle.
Complexity: O(n) time, O(1) space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Intel tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Intel, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: C, C++, Python, Verilog (role-dependent).
| Area | Why it matters at Intel |
|---|---|
| DSA | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Semiconductor, Computing awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |