Hexaware 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Hexaware placement papers from 2025 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Hexaware patterns and recent shifts.
Hexaware 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
Hexaware 2025 coding
DSA practice aligned to Hexaware online assessments
Hexaware interview experience
Round structure and tips from student reports
Hexaware prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
A can complete a work in 12 days, B in 15 days. They work together for 4 days, then A leaves. How long will B take to complete the remaining work?
Correct answer: 6 days
Quantitative
A sum of money doubles itself in 5 years at simple interest. In how many years will it become 4 times?
Correct answer: 15 years
Reasoning
Series: 1, 4, 9, 16, 25, ?
Perfect squares → 36.
Quantitative
The average of 5 numbers is 20. If one number is removed, the average becomes 18. Find the removed number.
Correct answer: 28
Reasoning
Statements: 1) Some boxes are cars, 2) Some cars are roads Conclusions: I) Some roads are boxes, II) Some cars are boxes, III) No box is a road, IV) Some roads are cars.
Correct answer: Only II and IV follow
Reasoning
A walks 3 km north, then 4 km east. Distance from start is:
3-4-5 right triangle → 5 km.
Quantitative
The ratio of present ages of father and son is 7:3. After 10 years, the ratio becomes 2:1. Find the present age of father.
Let present ages: Father = 7x, Son = 3x After 10 years: (7x + 10)/(3x + 10) = 2/1 7x + 10 = 2(3x + 10) 7x + 10 = 6x + 20 7x - 6x = 20 - 10 x = 10 Father's present age = 7 × 10 = 70 years
Verbal
Choose the correct form: "Neither the teacher nor the students _____ present."
Correct answer: were
Reasoning
Odd one out: Triangle, Square, Circle, Rectangle
Circle has no straight sides.
Verbal
One who loves books is a:
Bibliophile = lover of books.
Verbal
Find synonym of "Enormous"
Correct answer: Huge
Quantitative
The price of a product is increased by 25%. By what percentage should the consumption be reduced so that the expenditure remains the same?
Correct answer: 20%
Quantitative
What is 15% of 240?
15% of 240 = 0.15 × 240 = 36.
Verbal
Problem: "She is good _____ mathematics." a) at b) in c) on d) with
"Good at" is the correct prepositional phrase for skills.
Reasoning
Find next number: 3, 6, 12, 24, 48, ?
Pattern: Each number = previous × 2 3×2=6, 6×2=12, 12×2=24, 24×2=48 Next: 48×2 = 96
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Aptitude / logical | Quant, reasoning, sometimes verbal | Timed sectional accuracy |
| Coding / programming logic | Easy-medium DSA or output-style MCQs | Handle tricky inputs |
| Technical interview | OOPs, DBMS, OS, projects | Explain aloud |
| HR | Fit, location, intent | A few real examples ready |
First round: Hexaware Online Assessment
Skills emphasized: Aptitude, basic coding, communication
Languages: Java, Python, C++
These are practice-style questions aligned to patterns students report for Hexaware drives around 2025. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: A can finish a job in 10 days and B in 20 days. How long will they take working together?
Solution: A’s one-day work = 1/10. B’s one-day work = 1/20. Together = 1/10 + 1/20 = 3/20 per day. Time = 20/3 ≈ 6.67 days (6 days 16 hours).
Answer: 20/3 days
Problem: What is the sum of the first 50 natural numbers?
Solution: Sum of first n naturals = n(n+1)/2. For n = 50: 50 × 51 / 2 = 1275.
Answer: 1275
Problem: A person covers a distance at 60 km/h and returns at 40 km/h. What is the average speed for the whole trip?
Solution: For equal distances, average speed = 2ab/(a+b). = 2×60×40 / (60+40) = 4800/100 = 48 km/h.
Do not take the arithmetic mean (50); that would be wrong here.
Answer: 48 km/h
Problem: A shopkeeper marks goods 20% above cost and then gives a 10% discount. What is the profit percentage?
Solution: Let CP = ₹100. Marked price = ₹120. Discount = 10% of 120 = ₹12. SP = 120 − 12 = ₹108. Profit % = 8%.
Answer: 8%
Problem: A finishes work in 12 days, B in 15 days, and C in 20 days. Working together, how many days do they need?
Solution: Take total work = LCM(12,15,20) = 60 units. A = 5/day, B = 4/day, C = 3/day. Combined = 12 units/day. Time = 60/12 = 5 days.
Answer: 5 days
Problem: The ratio of ages of A and B is 3:5. After 8 years the ratio becomes 5:7. Find A’s present age.
Solution: Let ages be 3x and 5x. (3x+8)/(5x+8) = 5/7 7(3x+8) = 5(5x+8) 21x + 56 = 25x + 40 4x = 16 → x = 4 A’s age = 12 years.
Answer: 12 years
Problem: Pipe A fills a tank in 6 hours and pipe B in 8 hours. How long do they take together to fill it?
Solution: Combined rate = 1/6 + 1/8 = 4/24 + 3/24 = 7/24. Time = 24/7 hours ≈ 3 hours 26 minutes.
Answer: 24/7 hours
Problem: Find the simple interest on ₹8000 at 10% per annum for 2 years.
Solution: SI = (P × R × T) / 100 = (8000 × 10 × 2) / 100 = ₹1600.
Answer: ₹1600
Problem: Pointing to a photograph, Ravi says, ‘She is the daughter of my mother’s only son.’ How is the girl related to Ravi?
Solution: Ravi’s mother’s only son is Ravi himself (assuming one son). The girl is therefore Ravi’s daughter.
Answer: Daughter
Problem: Statements: All engineers are graduates. Some graduates are managers. Conclusion: Some engineers are managers. Does it follow?
Solution: The ‘some graduates’ who are managers need not overlap with the engineers. The conclusion does not follow necessarily.
Answer: Does not follow
Problem: A person walks 5 km north, then 3 km east, then 5 km south. How far is he from the start, and in which direction?
Solution: North 5 and south 5 cancel. He is 3 km east of the start.
Answer: 3 km east
Problem: Find the next number: 3, 9, 27, 81, ?
Solution: Each term is multiplied by 3. Next = 81 × 3 = 243.
Answer: 243
Problem: Given a list of intervals [start, end], merge all overlapping intervals and return the non-overlapping set that covers the same ranges.
Approach: Sort by start time. Walk once, merging into the last interval in the result when the next start is ≤ current end; otherwise append a new interval.
Complexity: O(n log n) time from the sort
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array and an integer k, return the k most frequent elements. Order among equals can be arbitrary unless the problem says otherwise.
Approach: Count frequencies with a hash map, then use a heap of size k (or bucket sort by frequency) to extract the top k keys.
Complexity: O(n log k) with a heap
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the head of a linked list, return true if there is a cycle and false otherwise.
Approach: Floyd’s tortoise and hare: move one pointer one step and another two steps. If they meet, a cycle exists. If the fast pointer hits null, there is no cycle.
Complexity: O(n) time, O(1) space
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
Hexaware tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Hexaware, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, Python, C++.
| Area | Why it matters at Hexaware |
|---|---|
| Aptitude | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| IT Services, Digital Transformation awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |
Mphasis · Virtusa · Coforge · Persistent Systems · CGI