Groww 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Groww placement papers from 2026 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Groww patterns and recent shifts.
Groww 2026 aptitude
Quantitative, reasoning, and verbal drills with solutions
Groww 2026 coding
DSA practice aligned to Groww online assessments
Groww interview experience
Round structure and tips from student reports
Groww prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
The following table shows the sales of a company over 5 years. Find the average annual growth rate. | Year | Sales (in crores) | |------|-------------------| | 2020 | 100 | | 2021 | 120 | | 2022 | 150 | | 2023 | 180 | | 2024 | 200 |
Correct answer: 19.03%
Verbal
If the cost price of 15 articles is equal to the selling price of 12 articles, find the profit percentage.
Let CP of 1 article = ₹1 CP of 15 articles = ₹15 SP of 12 articles = ₹15 (given) SP of 1 article = ₹15/12 = ₹1.25 Profit = SP - CP = ₹1.25 - ₹1 = ₹0.25 Profit % = (0.25/1) × 100 = 25%
Reasoning
Complete the series: AZ, BY, CX, ?
First letter +1, second −1 → DW.
Reasoning
All roses are flowers. Some flowers fade quickly. Conclusion: All roses fade quickly.
Only some flowers.
Quantitative
The HCF of 36 and 48 is:
36 = 2²×3², 48 = 2⁴×3 → HCF = 2²×3 = 12.
Reasoning
Find the next number: 11, 13, 17, 19, 23, ?
Prime numbers → 29.
Quantitative
A car covers 240 km in 4 hours. What is its average speed?
Correct answer: 60 km/hr
Verbal
Problem: Find the synonym of "ABUNDANT": a) Scarce b) Plentiful c) Limited d) Rare
Abundant means existing in large quantities, so "Plentiful" is the synonym.
Quantitative
Price rises by 25%. By what % should consumption fall to keep expenditure the same?
Reduction = 25/(100+25)×100 = 20%.
Verbal
Fill in: She is good _____ mathematics.
Good at a subject.
Verbal
Synonym of "Abundant":
Abundant means plentiful.
Reasoning
All pens are books. Some books are papers. Conclusion: Some pens are papers.
No definite overlap between pens and papers.
Quantitative
A train 150m long passes a platform 200m long in 14 seconds. Find the speed of the train.
Correct answer: 90 km/hr
Reasoning
Statement: All roses are flowers. Some flowers are red.
From "All roses are flowers" and "Some flowers are red", we cannot conclude that some roses are red (I may not follow) "All red things are flowers" is not necessarily true (II does not follow)
Quantitative
Identify the error: "The data shows that the results are positive."
Correct answer: Subject-verb agreement error
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Online assessment | Coding and/or MCQ filter | Weekly timed mocks |
| Technical rounds | DSA, CS fundamentals, projects | Live problem solving |
| HR / hiring manager | Motivation and communication | Specific, evidence-based answers |
First round: Groww Online Assessment
Skills emphasized: DSA, fintech systems
Languages: Java, Kotlin, Python
These are practice-style questions aligned to patterns students report for Groww drives around 2026. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: A can finish a job in 10 days and B in 20 days. How long will they take working together?
Solution: A’s one-day work = 1/10. B’s one-day work = 1/20. Together = 1/10 + 1/20 = 3/20 per day. Time = 20/3 ≈ 6.67 days (6 days 16 hours).
Answer: 20/3 days
Problem: What is the sum of the first 50 natural numbers?
Solution: Sum of first n naturals = n(n+1)/2. For n = 50: 50 × 51 / 2 = 1275.
Answer: 1275
Problem: A person covers a distance at 60 km/h and returns at 40 km/h. What is the average speed for the whole trip?
Solution: For equal distances, average speed = 2ab/(a+b). = 2×60×40 / (60+40) = 4800/100 = 48 km/h.
Do not take the arithmetic mean (50); that would be wrong here.
Answer: 48 km/h
Problem: A shopkeeper marks goods 20% above cost and then gives a 10% discount. What is the profit percentage?
Solution: Let CP = ₹100. Marked price = ₹120. Discount = 10% of 120 = ₹12. SP = 120 − 12 = ₹108. Profit % = 8%.
Answer: 8%
Problem: A finishes work in 12 days, B in 15 days, and C in 20 days. Working together, how many days do they need?
Solution: Take total work = LCM(12,15,20) = 60 units. A = 5/day, B = 4/day, C = 3/day. Combined = 12 units/day. Time = 60/12 = 5 days.
Answer: 5 days
Problem: The ratio of ages of A and B is 3:5. After 8 years the ratio becomes 5:7. Find A’s present age.
Solution: Let ages be 3x and 5x. (3x+8)/(5x+8) = 5/7 7(3x+8) = 5(5x+8) 21x + 56 = 25x + 40 4x = 16 → x = 4 A’s age = 12 years.
Answer: 12 years
Problem: Pipe A fills a tank in 6 hours and pipe B in 8 hours. How long do they take together to fill it?
Solution: Combined rate = 1/6 + 1/8 = 4/24 + 3/24 = 7/24. Time = 24/7 hours ≈ 3 hours 26 minutes.
Answer: 24/7 hours
Problem: Find the simple interest on ₹8000 at 10% per annum for 2 years.
Solution: SI = (P × R × T) / 100 = (8000 × 10 × 2) / 100 = ₹1600.
Answer: ₹1600
Problem: Given the root of a binary tree, return the level-order traversal (breadth-first) as a list of levels.
Approach: Use a queue. For each level, drain the current queue size, collect values, and enqueue children for the next level.
Complexity: O(n) time, O(n) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Find the first non-repeating character in a string and return its index, or -1 if none exists.
Approach: Count frequencies in one pass (hash map or array of 26 for lowercase). Second pass returns the first index with count 1.
Complexity: O(n) time
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Design a stack that supports push, pop, top, and getMin in average O(1) time.
Approach: Keep a parallel min-stack (or store pairs). When pushing, also push the new minimum. When popping, pop both stacks.
Complexity: O(1) per operation amortized
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array, find the contiguous subarray with the largest sum and return that sum. Example: [-2,1,-3,4,-1,2,1,-5,4] → 6 (from [4,-1,2,1]).
Approach: Keep a running sum. If the running sum drops below 0, reset it to 0 before taking the next element (or track the best ending-here value). Track the global maximum as you scan once from left to right.
Complexity: O(n) time, O(1) extra space
Groww tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Groww, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, Kotlin, Python.
| Area | Why it matters at Groww |
|---|---|
| DSA | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Investment Platform awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |