Globant 2024 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects Globant placement papers from 2024 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established Globant patterns and recent shifts.
Globant 2024 aptitude
Quantitative, reasoning, and verbal drills with solutions
Globant 2024 coding
DSA practice aligned to Globant online assessments
Globant interview experience
Round structure and tips from student reports
Globant prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Quantitative
Successive discounts of 20% and 10% are equivalent to a single discount of:
Effective = 100 − 80×90/100 = 28%.
Quantitative
What is the output for gcd(48, 18)?
Correct answer: 6
Verbal
Fill in the blank: She _____ to the office every day by metro.
Third-person singular present tense takes "goes".
Verbal
Find the synonym of "Benevolent".
Correct answer: Kind
Reasoning
Find the next number: 5, 10, 20, 40, ?
×2 each → 80.
Reasoning
Find next number: 3, 6, 12, 24, 48, ?
Pattern: Each number = previous × 2 3×2=6, 6×2=12, 12×2=24, 24×2=48 Next: 48×2 = 96
Reasoning
Two trains of lengths 200m and 300m are moving in opposite directions at speeds of 50 km/hr and 40 km/hr. Find the time taken to cross each other.
Correct answer: 20 seconds
Verbal
Problem: Choose the synonym for "Ephemeral": a) Eternal b) Transient c) Permanent d) Perpetual
"Ephemeral" means lasting for a very short time, temporary. "Transient" has the same meaning.
Quantitative
Find the smallest number that must be added to 1056 to make it divisible by 23.
1056 ÷ 23 = 45 remainder 21 Number to add = 23 - 21 = 2
Quantitative
The sum of ages of 5 children born at intervals of 3 years is 50 years. Find the age of the youngest child.
Let youngest child's age = x Ages: x, x+3, x+6, x+9, x+12 Sum = 5x + 30 = 50 5x = 20 x = 4 years
Reasoning
Find the next number: 2, 6, 12, 20, 30, ?
Differences +4, +6, +8, +10, +12 → next is 42.
Quantitative
A and B can complete a work in 20 days and 30 days respectively. They work together for 6 days, then A leaves. In how many days will B complete the remaining work?
A's 1 day work = 1/20 B's 1 day work = 1/30 Together in 1 day = 1/20 + 1/30 = 5/60 = 1/12 Work done in 6 days = 6 × 1/12 = 1/2 Remaining work = 1 - 1/2 = 1/2 B will complete in = (1/2) / (1/30) = 15 days
Verbal
A shopkeeper sells an article at a profit of 20%. If the cost price is ₹500, find the selling price.
CP = ₹500 Profit = 20% of 500 = ₹100 SP = CP + Profit = 500 + 100 = ₹600
Reasoning
All pens are books. Some books are papers. Conclusion: Some pens are papers.
No definite overlap between pens and papers.
Quantitative
In what ratio should water be mixed with milk costing ₹12 per liter to get a mixture worth ₹8 per liter?
Using alligation: Water (₹0) Milk (₹12) \ / \ / \ / \ / \ / ₹8 Ratio = (12-8):(8-0) = 4:8 = 1:2
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Aptitude / logical | Quant, reasoning, sometimes verbal | Timed sectional accuracy |
| Coding / programming logic | Easy-medium DSA or output-style MCQs | Handle tricky inputs |
| Technical interview | OOPs, DBMS, OS, projects | Explain aloud |
| HR | Fit, location, intent | A few real examples ready |
First round: Globant Assessment
Skills emphasized: Coding, OOPs, agile mindset
Languages: Java, JavaScript, Python
These are practice-style questions aligned to patterns students report for Globant drives around 2024. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: The average of five numbers is 20. One number 30 is replaced by 10. What is the new average?
Solution: Old sum = 5 × 20 = 100. New sum = 100 − 30 + 10 = 80. New average = 80 / 5 = 16.
Answer: 16
Problem: Find the next term: 2, 6, 12, 20, 30, ?
Solution: Pattern: 1×2, 2×3, 3×4, 4×5, 5×6, 6×7. Next = 6 × 7 = 42.
Answer: 42
Problem: What is the probability of drawing an ace from a standard 52-card deck?
Solution: There are 4 aces in 52 cards. Probability = 4/52 = 1/13.
Answer: 1/13
Problem: A number is increased by 20% and then decreased by 20%. What is the net percentage change?
Solution: Start with 100 → 120 → 96. Net change = 4% decrease. Formula: successive +a then −a gives −(a²/100)% = −4%.
Answer: 4% decrease
Problem: If the price of an item rises by 25%, by what percent should consumption fall so that expenditure stays the same?
Solution: Required reduction = r/(100+r) × 100 with r = 25. = 25/125 × 100 = 20%.
Answer: 20%
Problem: An article is marked 40% above cost and sold after a 10% discount. Find the profit percent.
Solution: SP = CP × 1.4 × 0.9 = 1.26 CP. Profit = 26%.
Answer: 26%
Problem: An article sold at 10% loss would give 5% profit if sold for ₹60 more. Find the cost price.
Solution: 0.9P + 60 = 1.05P 60 = 0.15P P = 60 / 0.15 = ₹400.
Answer: ₹400
Problem: Eight workers finish a job in 10 days. How many days will 10 workers take for the same job (same pace)?
Solution: Total man-days = 8 × 10 = 80. Days for 10 workers = 80 / 10 = 8 days.
Answer: 8 days
Problem: If CAT is coded as DBU, how is DOG coded in the same way?
Solution: Each letter moves +1 in the alphabet: C→D, A→B, T→U. D→E, O→P, G→H → EPH.
Answer: EPH
Problem: Pointing to a photograph, Ravi says, ‘She is the daughter of my mother’s only son.’ How is the girl related to Ravi?
Solution: Ravi’s mother’s only son is Ravi himself (assuming one son). The girl is therefore Ravi’s daughter.
Answer: Daughter
Problem: Statements: All engineers are graduates. Some graduates are managers. Conclusion: Some engineers are managers. Does it follow?
Solution: The ‘some graduates’ who are managers need not overlap with the engineers. The conclusion does not follow necessarily.
Answer: Does not follow
Problem: A person walks 5 km north, then 3 km east, then 5 km south. How far is he from the start, and in which direction?
Solution: North 5 and south 5 cancel. He is 3 km east of the start.
Answer: 3 km east
Problem: Given a mutable character array representing a string, reverse it in place without allocating another array of the same size.
Approach: Use two pointers at the start and end. Swap characters, then move inward until the pointers meet. Watch empty and single-character inputs.
Complexity: O(n) time, O(1) extra space
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Write a function that returns true if n is prime and false otherwise. Handle n < 2 correctly.
Approach: Return false for n < 2. Trial-divide from 2 to floor(sqrt(n)). If any divisor divides n evenly, it is composite; otherwise prime.
Complexity: O(√n) time
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a string containing only ‘()[]’, decide whether the brackets are balanced and correctly nested.
Approach: Scan left to right with a stack. Push opening brackets. On a closing bracket, the stack top must be the matching opener. At the end the stack must be empty.
Complexity: O(n) time, O(n) space
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an array of integers and a target, return indices of two numbers that add up to the target. Assume exactly one solution and you may not use the same element twice.
Approach: Walk the array once. For each value x, check whether target − x was seen earlier in a hash map of value → index. If yes, return both indices; else store x.
Complexity: O(n) time, O(n) space
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a string s, find the length of the longest substring without repeating characters. Example: ‘abcabcbb’ → 3 (‘abc’).
Approach: Sliding window with a map (or last-seen index) of characters. Expand the right pointer; when a duplicate appears inside the window, move the left pointer past the previous occurrence.
Complexity: O(n) time
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a list of intervals [start, end], merge all overlapping intervals and return the non-overlapping set that covers the same ranges.
Approach: Sort by start time. Walk once, merging into the last interval in the result when the next start is ≤ current end; otherwise append a new interval.
Complexity: O(n log n) time from the sort
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array and an integer k, return the k most frequent elements. Order among equals can be arbitrary unless the problem says otherwise.
Approach: Count frequencies with a hash map, then use a heap of size k (or bucket sort by frequency) to extract the top k keys.
Complexity: O(n log k) with a heap
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given the head of a linked list, return true if there is a cycle and false otherwise.
Approach: Floyd’s tortoise and hare: move one pointer one step and another two steps. If they meet, a cycle exists. If the fast pointer hits null, there is no cycle.
Complexity: O(n) time, O(1) space
Globant tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For Globant, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, JavaScript, Python.
| Area | Why it matters at Globant |
|---|---|
| Coding | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Digital Products, AI Studios awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |