EPAM 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
This page collects EPAM placement papers from 2025 with practice questions, worked solutions, and the exam pattern students reported that cycle. Use it when you want drive history: what the first round looked like, which topics repeated, and how to approach solutions. Work the sets below under a timer, then compare with newer material so your prep matches both established EPAM patterns and recent shifts.
EPAM 2025 aptitude
Quantitative, reasoning, and verbal drills with solutions
EPAM 2025 coding
DSA practice aligned to EPAM online assessments
EPAM interview experience
Round structure and tips from student reports
EPAM prep guide
Study plan and weekly schedule
Timed placement-style MCQs with score and explanations after you submit. Use it to check speed and accuracy before the real test.
Reasoning
Find the next number: 2, 6, 12, 20, 30, ?
Differences +4, +6, +8, +10, +12 → next is 42.
Reasoning
Statements: All cats are dogs. Some dogs are birds. Conclusions: I. Some cats are birds. II. All birds are cats.
Analyzing the statements: - All cats are dogs (A → B) - Some dogs are birds (B → C, some) Conclusion I: Some cats are birds - Since all cats are dogs, and some dogs are birds, we can say some cats are birds. Valid Conclusion II: All birds are cats - This canno
Quantitative
A and B finish a job in 12 and 18 days. Working together they finish in:
1/12 + 1/18 = 5/36 → 36/5 = 7.2 days.
Reasoning
Find next number: 1, 4, 9, 16, 25, ?
Pattern: n² where n = 1, 2, 3, 4, 5... 1²=1, 2²=4, 3²=9, 4²=16, 5²=25 Next: 6² = 36
Verbal
"Break the ice" means:
It means to initiate conversation in a social setting.
Verbal
Antonym of "Benevolent":
Benevolent ↔ malevolent.
Verbal
There _____ many books on the table.
Many books → plural.
Quantitative
A can complete a work in 10 days, B in 15 days. In how many days will they complete the work together?
Let total work = LCM of 10, 15 = 30 units A's efficiency = 30/10 = 3 units/day B's efficiency = 30/15 = 2 units/day Combined efficiency = 3 + 2 = 5 units/day Time taken = 30/5 = 6 days
Quantitative
If "APPLE" is coded as "BQQMF", how is "ORANGE" coded?
Correct answer: PSBOHF
Reasoning
Find the next number: 3, 9, 27, 81, ?
×3 each → 243.
Quantitative
Five people A, B, C, D, E sit in a row. A is not at either end. B sits next to A. C sits at one end. D sits between C and E. Who sits in the middle?
C is at one end. D is between C and E, so: C-D-E or E-D-C A is not at end, B is next to A If C-D-E, then A-B must be before: A-B-C-D-E (A at end, invalid) So: E-D-C, and A-B before: A-B-E-D-C Middle position: E
Verbal
He _____ to school every day.
Singular present.
Quantitative
A shopkeeper marks goods 40% above cost and gives a 10% discount. Profit % is:
SP = 1.4 × 0.9 × CP = 1.26 CP → 26% profit.
Quantitative
Speed 72 km/h. Distance in 20 minutes:
72 × (20/60) = 24 km.
Reasoning
If letter positions are summed (A=1…Z=26), PEN equals:
Sum of positions = 35.
Your score
0/15(0%)
| Section | What shows up | Prep focus |
|---|---|---|
| Aptitude / logical | Quant, reasoning, sometimes verbal | Timed sectional accuracy |
| Coding / programming logic | Easy-medium DSA or output-style MCQs | Handle tricky inputs |
| Technical interview | OOPs, DBMS, OS, projects | Explain aloud |
| HR | Fit, location, intent | A few real examples ready |
First round: EPAM Codility / Online Test
Skills emphasized: DSA, CS fundamentals, communication
Languages: Java, JavaScript, Python, C#
These are practice-style questions aligned to patterns students report for EPAM drives around 2025. They are not leaked live papers. Work them timed, then read the solutions only after you have an answer.
Problem: If the price of an item rises by 25%, by what percent should consumption fall so that expenditure stays the same?
Solution: Required reduction = r/(100+r) × 100 with r = 25. = 25/125 × 100 = 20%.
Answer: 20%
Problem: An article is marked 40% above cost and sold after a 10% discount. Find the profit percent.
Solution: SP = CP × 1.4 × 0.9 = 1.26 CP. Profit = 26%.
Answer: 26%
Problem: An article sold at 10% loss would give 5% profit if sold for ₹60 more. Find the cost price.
Solution: 0.9P + 60 = 1.05P 60 = 0.15P P = 60 / 0.15 = ₹400.
Answer: ₹400
Problem: Eight workers finish a job in 10 days. How many days will 10 workers take for the same job (same pace)?
Solution: Total man-days = 8 × 10 = 80. Days for 10 workers = 80 / 10 = 8 days.
Answer: 8 days
Problem: A vehicle travels at 60 km/h for 2.5 hours. How far does it go?
Solution: Distance = speed × time = 60 × 2.5 = 150 km.
Answer: 150 km
Problem: If two ratios are 3:5 and 5:7, what is the compound ratio?
Solution: Compound ratio = (3/5) × (5/7) = 3/7, written as 3:7.
Answer: 3:7
Problem: Find simple interest on ₹5000 at 8% per annum for 3 years.
Solution: SI = 5000 × 8 × 3 / 100 = ₹1200.
Answer: ₹1200
Problem: A boat’s speed in still water is 15 km/h and the stream is 3 km/h. How long to cover 36 km upstream?
Solution: Upstream speed = 15 − 3 = 12 km/h. Time = 36 / 12 = 3 hours.
Answer: 3 hours
Problem: Statements: All engineers are graduates. Some graduates are managers. Conclusion: Some engineers are managers. Does it follow?
Solution: The ‘some graduates’ who are managers need not overlap with the engineers. The conclusion does not follow necessarily.
Answer: Does not follow
Problem: A person walks 5 km north, then 3 km east, then 5 km south. How far is he from the start, and in which direction?
Solution: North 5 and south 5 cancel. He is 3 km east of the start.
Answer: 3 km east
Problem: Find the next number: 3, 9, 27, 81, ?
Solution: Each term is multiplied by 3. Next = 81 × 3 = 243.
Answer: 243
Problem: Five friends sit in a row. A is to the left of B but right of C. D is to the right of B and left of E. Who is in the middle?
Solution: Order from left to right: C, A, B, D, E. The middle seat is B.
Answer: B
Problem: Given coin denominations and an amount, return the fewest coins needed to make that amount, or -1 if it is impossible.
Approach: Unbounded knapsack DP: let dp[x] be the minimum coins for amount x. For each coin, update dp[c..amount]. Initialize dp[0] = 0 and the rest to a large sentinel.
Complexity: O(amount × coins)
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a sorted array of distinct integers and a target, return the index of target or -1 if missing.
Approach: Maintain lo/hi. Compare mid with target and shrink the half that cannot contain it. Careful with overflow-free mid and empty arrays.
Complexity: O(log n) time
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Move all zeros in an array to the end while keeping the relative order of non-zero elements.
Approach: Two pointers: write non-zeros toward the front, then fill the remainder with zeros. Or swap zeros as you scan.
Complexity: O(n) time, O(1) space
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Rotate an array to the right by k steps. Example: [1,2,3,4,5,6,7], k = 3 → [5,6,7,1,2,3,4].
Approach: Normalize k %= n. Reverse the whole array, reverse the first k elements, then reverse the rest. That yields the rotation in place.
Complexity: O(n) time, O(1) space
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Find the first non-repeating character in a string and return its index, or -1 if none exists.
Approach: Count frequencies in one pass (hash map or array of 26 for lowercase). Second pass returns the first index with count 1.
Complexity: O(n) time
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Design a stack that supports push, pop, top, and getMin in average O(1) time.
Approach: Keep a parallel min-stack (or store pairs). When pushing, also push the new minimum. When popping, pop both stacks.
Complexity: O(1) per operation amortized
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given an integer array, find the contiguous subarray with the largest sum and return that sum. Example: [-2,1,-3,4,-1,2,1,-5,4] → 6 (from [4,-1,2,1]).
Approach: Keep a running sum. If the running sum drops below 0, reset it to 0 before taking the next element (or track the best ending-here value). Track the global maximum as you scan once from left to right.
Complexity: O(n) time, O(1) extra space
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Problem: Given a mutable character array representing a string, reverse it in place without allocating another array of the same size.
Approach: Use two pointers at the start and end. Swap characters, then move inward until the pointers meet. Watch empty and single-character inputs.
Complexity: O(n) time, O(1) extra space
EPAM tip: Restate the problem, sketch a brute-force idea, then tighten it. Call out edge cases (empty input, single element, overflow) before you write code.
Students usually say the first round is time-tight - easy marks vanish if you sit too long on one hard question. For EPAM, skim the paper in a couple of minutes, mark what you can finish cleanly, and protect accuracy. Languages people commonly use: Java, JavaScript, Python, C#.
| Area | Why it matters at EPAM |
|---|---|
| DSA | What usually helps you clear the first round |
| Core CS (OOPs / DBMS / OS) | Technical interview depth |
| Software Engineering, Digital Platforms awareness | Helps in managerial / HR conversations |
| Communication | Explain your approach clearly; keep a few real examples ready for HR |
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