Deutsche Bank 2025 papers
Latest Deutsche Bank placement papers with current year questions
This page collects Deutsche Bank placement papers from 2024 with previous-year questions, solutions, and the 2024 exam pattern. It is useful when you want real drive history: what the OA looked like, which question types repeated, and how solutions were approached. Work through the papers below to build speed and accuracy, then compare against newer 2025 material so your prep matches both established Deutsche Bank patterns and the latest shifts.
| Section | Questions | Time | Difficulty |
|---|---|---|---|
| Coding Problems | 2-3 | 90 min | Medium-Hard |
This section contains practice questions styled on Deutsche Bank placement papers 2024 (previous-year pattern), with worked solutions. Use them as timed sectional drills - from student reports drives vary by college and role, so treat this as a high-signal practice bank, not an official paper dump.
Solution:
SI = (P × R × T)/100 = (5000 × 8 × 3)/100 = ₹1200.
Answer: ₹1200
Solution:
Together rate = 1/10. B’s rate = 1/15.
A’s rate = 1/10 − 1/15 = (15−10)/(10×15) = 5/150. Days for A alone = 150/5 = 30 days.
Answer: 30 days
Solution:
Let ages be 2x and 3x.
(2x + 6)/(3x + 6) = 3/4 4(2x + 6) = 3(3x + 6) 8x + 24 = 9x + 18 x = 6 A’s age = 2×6 = 12 years.
Answer: 12 years
Solution:
Let original = 100. After +10% → 110. After −10% → 110 − 11 = 99.
Net change = 100 − 99 = 1. Net % = 1% decrease (always a loss of (10/10)² %).
Answer: 1% decrease
Solution:
From the statements, papers⊆items and some items overlap cheap. That does not force some papers to be cheap, and ‘all items are papers’ reverses the first statement wrongly.
Neither conclusion follows.
Answer: Neither I nor II follows
Solution:
Pattern: positions concatenated T=20,I=9,P=16
Therefore TIP → 20916.
Answer: 20916
Solution:
‘Transparent’ means roughly the opposite of Opaque.
Answer: Opaque
Solution:
Natural order: Q-R-P-S → Hard work is essential to succeed in any field.
Answer: QRPS
Problem Statement: Return the level-order traversal of a binary tree.
Example:
Input: [3,9,20,null,null,15,7]Output: [[3],[9,20],[15,7]]Solution (Java):
public List<List<Integer>> levelOrder(TreeNode root) { List<List<Integer>> res = new ArrayList<>(); if (root == null) return res; Queue<TreeNode> q = new ArrayDeque<>(); q.add(root); while (!q.isEmpty()) { int sz = q.size(); List<Integer> level = new ArrayList<>(); for (int i = 0; i < sz; i++) { TreeNode n = q.poll(); level.add(n.val); if (n.left != null) q.add(n.left); if (n.right != null) q.add(n.right); } res.add(level); } return res;}Time Complexity: O(n)
Space Complexity: O(n)
Problem Statement: Given an array of integers and a target, return indices of two numbers that add up to target.
Example:
Input: nums = [2, 7, 11, 15], target = 9Output: [0, 1]Solution (Java):
public int[] twoSum(int[] nums, int target) { Map<Integer, Integer> map = new HashMap<>(); for (int i = 0; i < nums.length; i++) { int need = target - nums[i]; if (map.containsKey(need)) return new int[]{map.get(need), i}; map.put(nums[i], i); } return new int[]{};}Time Complexity: O(n)
Space Complexity: O(n)
Problem Statement: Rotate the array to the right by k steps.
Example:
Input: [1,2,3,4,5,6,7], k = 3Output: [5,6,7,1,2,3,4]Solution (Java):
public void rotate(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1);}void reverse(int[] a, int l, int r) { while (l < r) { int t = a[l]; a[l++] = a[r]; a[r--] = t; }}Time Complexity: O(n)
Space Complexity: O(1)
Based on candidate experiences from 2024 Deutsche Bank interviews:
2024 Interview Process:
Common 2024 Interview Topics:
2024 Interview Questions Examples:
Success Tips:
For detailed interview experiences, visit Deutsche Bank Interview Experience page.
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