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Download TCS placement papers 2024 PDF with previous year NQT questions, solutions, and exam pattern analysis for 2024 recruitment cycle.
This page contains TCS placement papers from 2024 with previous year NQT questions, solutions, and exam patterns. Use these papers to understand the 2024 TCS NQT pattern and practice with actual questions from TCS placement papers 2024.
The TCS National Qualifier Test (NQT) 2024 is divided into two main parts:
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Numerical Ability | 20 | 25 min | Medium | Quantitative aptitude, percentages, ratios, time & work |
| Verbal Ability | 25 | 25 min | Medium | English grammar, reading comprehension, vocabulary |
| Reasoning Ability | 20 | 25 min | Medium | Logical reasoning, puzzles, syllogism |
Part A Total: 65 questions, 75 minutes
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Advanced Quantitative + Reasoning | 15 | 25 min | Medium-Hard | Advanced quantitative problems, complex reasoning |
| Advanced Coding | 3 | 90 min | Medium-Hard | Hands-on coding problems, algorithms, data structures |
Part B Total: 18 questions, 115 minutes
Overall Total: 83 questions, 190 minutes (3 hours 10 minutes)
Platform: TCS iON platform
Languages Allowed: C, C++, Java, Python
Success Rate: ~20-25% cleared NQT and advanced to interviews
This section contains real questions from TCS NQT 2024 based on candidate experiences from GeeksforGeeks, PrepInsta, and interview forums.
Solution:
Let CP = ₹100 Marked Price (MP) = 100 + 20% of 100 = ₹120 Discount = 10% of 120 = ₹12 Selling Price (SP) = 120 - 12 = ₹108 Profit = 108 - 100 = ₹8 Profit % = (8/100) × 100 = 8%
Answer: 8%
Solution:
Let total work = LCM of 12, 15, 20 = 60 units
A’s efficiency = 60/12 = 5 units/day B’s efficiency = 60/15 = 4 units/day C’s efficiency = 60/20 = 3 units/day
Combined efficiency = 5 + 4 + 3 = 12 units/day Time taken = 60/12 = 5 days
Answer: 5 days
Solution:
Let present ages be 3x and 5x.
After 8 years:
Given: (3x + 8)/(5x + 8) = 5/7
7(3x + 8) = 5(5x + 8) 21x + 56 = 25x + 40 4x = 16 x = 4
Present age of A = 3x = 3 × 4 = 12 years
Answer: 12 years
Answer: Job displacement and ethical implications
Explanation: The passage explicitly mentions concerns about job displacement and ethical implications as significant issues related to AI.
Error: “were” should be “was”
Correct Sentence: “Neither of the students was present in the class.”
Explanation: “Neither” is singular and requires singular verb “was”.
Solution:
Analyzing the statements:
Conclusion I: Some cats are dogs
Conclusion II: All dogs are cats
Answer: Neither conclusion follows
Solution:
Pattern analysis:
Pattern: Position of letter in alphabet
For “RAT”:
Answer: “18120”
#include <stdio.h>int main() { int x = 5; printf("%d", x++ + ++x); return 0;}Solution:
x++ is post-increment: uses value 5, then increments to 6 ++x is pre-increment: increments 6 to 7, then uses value 7
Result: 5 + 7 = 12
Answer: 12
Problem Statement: Given an array of integers, find the second largest element.
Example:
Input: [12, 35, 1, 10, 34, 1]Output: 34Solution (Java):
public int findSecondLargest(int[] arr) { if (arr.length < 2) return -1;
int largest = Integer.MIN_VALUE; int secondLargest = Integer.MIN_VALUE;
for (int num : arr) { if (num > largest) { secondLargest = largest; largest = num; } else if (num > secondLargest && num != largest) { secondLargest = num; } }
return secondLargest == Integer.MIN_VALUE ? -1 : secondLargest;}Time Complexity: O(n)
Space Complexity: O(1)
Problem Statement: Given a string, reverse the order of words.
Example:
Input: "the sky is blue"Output: "blue is sky the"Solution (Java):
public String reverseWords(String s) { String[] words = s.trim().split("\\s+"); StringBuilder result = new StringBuilder();
for (int i = words.length - 1; i >= 0; i--) { result.append(words[i]); if (i > 0) result.append(" "); }
return result.toString();}Time Complexity: O(n)
Space Complexity: O(n)
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