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Adobe OA Coding Section:
Solution (Java):
public int[] productExceptSelf(int[] nums) { int n = nums.length; int[] result = new int[n]; result[0] = 1;
for (int i = 1; i < n; i++) { result[i] = result[i-1] * nums[i-1]; }
int right = 1; for (int i = n-1; i >= 0; i--) { result[i] *= right; right *= nums[i]; }
return result;}Time Complexity: O(n)
Adobe 2024 Papers
Previous year papers with coding questions
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