Skip to content

Accenture Placement Papers 2025 - Latest NLT Questions & Solutions

Access free Accenture placement papers 2025, latest NLT questions with solutions, detailed exam pattern, interview questions, and complete preparation guide. Download Accenture 2025 placement papers PDF.

This page contains Accenture placement papers from 2025 with the latest questions, solutions, and exam patterns. Use these current year papers to prepare effectively for Accenture NLT and interviews.

The 2025 exam pattern remains similar to 2024. For detailed exam pattern, see 2024 Papers.

Note: The pattern may have minor variations. Check the latest updates from the company.

This section contains real questions from Accenture NLT 2025 based on candidate experiences and actual exam patterns. All questions include detailed solutions and explanations.

Q1: Percentage Problem (2025)

Problem: The price of a product increased by 20%. By what percentage should consumption be reduced to keep expenditure same?

Solution: Let original price = ₹100, consumption = 100 units New price = ₹120 Original expenditure = ₹10,000 New consumption = 10,000 / 120 = 83.33 units Reduction = (100 - 83.33) / 100 × 100 = 16.67%

Answer: 16.67%

Q2: Mixture Problem (2025)

Problem: A mixture contains milk and water in ratio 3:2. If 10 liters of water is added, ratio becomes 2:3. Find initial quantity of mixture.

Solution: Let initial: Milk = 3x, Water = 2x After adding 10L water: Milk = 3x, Water = 2x + 10 3x / (2x + 10) = 2/3 9x = 4x + 20 5x = 20 x = 4 Initial quantity = 3x + 2x = 5x = 20 liters

Answer: 20 liters

Q3: Profit & Loss - Successive Discounts (2025)

Problem: A shopkeeper gives two successive discounts of 10% and 20% on an item. What is the effective discount percentage?

Solution: Let MP = ₹100 After first discount: 100 - 10% = ₹90 After second discount: 90 - 20% = ₹72 Effective discount = (100 - 72) / 100 × 100 = 28%

Answer: 28%

Q4: Time & Work - Efficiency (2025)

Problem: A is twice as efficient as B. Together they complete a work in 12 days. In how many days will A alone complete it?

Solution: Let B’s efficiency = 1 unit/day A’s efficiency = 2 units/day Together: 1 + 2 = 3 units/day Total work = 3 × 12 = 36 units A alone: 36 / 2 = 18 days

Answer: 18 days

Q5: Simple Interest - Rate Calculation (2025)

Problem: A sum of ₹8,000 amounts to ₹9,600 in 4 years at simple interest. Find the rate of interest per annum.

Solution: Principal = ₹8,000, Amount = ₹9,600 Interest = 9,600 - 8,000 = ₹1,600 SI = P × R × T / 100 1,600 = 8,000 × R × 4 / 100 R = (1,600 × 100) / (8,000 × 4) = 5%

Answer: 5% per annum

Q6: Compound Interest - Half Yearly (2025)

Problem: Find compound interest on ₹5,000 for 1 year at 10% per annum, compounded half-yearly.

Solution: Rate per half year = 10/2 = 5% Number of periods = 2 Amount = 5000(1 + 5/100)² = 5000 × 1.05² = 5000 × 1.1025 = ₹5,512.50 CI = 5,512.50 - 5,000 = ₹512.50

Answer: ₹512.50

Q7: Speed & Distance - Relative Speed (2025)

Problem: Two trains of lengths 100m and 150m are running in the same direction at speeds of 50 km/hr and 40 km/hr respectively. Find the time taken by faster train to overtake the slower train.

Solution: Relative speed = 50 - 40 = 10 km/hr = 10 × 5/18 = 25/9 m/s Distance to cover = 100 + 150 = 250m Time = 250 / (25/9) = 250 × 9/25 = 90 seconds

Answer: 90 seconds

Q8: Speed & Distance - Average Speed (2025)

Problem: A person travels first half of distance at 40 km/hr and second half at 60 km/hr. Find average speed.

Solution: Let total distance = 2D Time for first half = D/40 Time for second half = D/60 Total time = D/40 + D/60 = D(3+2)/120 = 5D/120 = D/24 Average speed = 2D / (D/24) = 48 km/hr

Answer: 48 km/hr

Q9: Permutations - Arrangements (2025)

Problem: In how many ways can 5 people be arranged in a row if two particular people must sit together?

Solution: Treat the two people as one unit: 4 units to arrange = 4! ways The two people can be arranged among themselves in 2! ways Total = 4! × 2! = 24 × 2 = 48 ways

Answer: 48 ways

Q10: Combinations - Selection (2025)

Problem: In how many ways can 3 students be selected from a group of 8 students?

Solution: Number of ways = C(8,3) = 8! / (3! × 5!) = (8 × 7 × 6) / (3 × 2 × 1) = 56

Answer: 56 ways

Q11: Pipes & Cisterns - Multiple Pipes (2025)

Problem: Three pipes A, B, C can fill a tank in 12, 15, and 20 hours respectively. If all three are opened together, how long will it take to fill the tank?

Solution: A’s rate = 1/12 per hour B’s rate = 1/15 per hour C’s rate = 1/20 per hour Combined rate = 1/12 + 1/15 + 1/20 = (5+4+3)/60 = 12/60 = 1/5 per hour Time = 1 / (1/5) = 5 hours

Answer: 5 hours

Q12: Probability - Cards (2025)

Problem: Two cards are drawn from a pack of 52 cards. What is the probability that both are aces?

Solution: Probability = (4/52) × (3/51) = (1/13) × (1/17) = 1/221

Answer: 1/221

Q13: Ratio & Proportion - Three Quantities (2025)

Problem: If A:B = 2:3 and B:C = 4:5, find A:B:C.

Solution: A:B = 2:3 = 8:12 (multiply by 4) B:C = 4:5 = 12:15 (multiply by 3) A:B:C = 8:12:15

Answer: 8:12:15

Q14: Percentage - Successive Changes (2025)

Problem: A number is first increased by 25% and then decreased by 20%. Find the net percentage change.

Solution: Let number = 100 After 25% increase: 100 + 25 = 125 After 20% decrease: 125 - 20% of 125 = 125 - 25 = 100 Net change = 0%

Answer: 0% (no change)

Q15: Data Interpretation (2025)

Problem: The table shows sales (in thousands) for 5 products. If Product A sold 25% more than Product B, and Product B sold 40,000 units, find Product A’s sales.

Solution: Product B = 40,000 Product A = 40,000 + 25% of 40,000 = 40,000 + 10,000 = 50,000

Answer: 50,000 units

Q16: Ages Problem - Sum of Ages (2025 - Real Question)

Problem: The sum of the ages of A and B is 60 years, and A is twice as old as B, what are their ages?

Solution: Let B’s age be x years Then A’s age is 2x years x + 2x = 60 3x = 60 x = 20

B’s age = 20 years A’s age = 40 years

Answer: A: 40 years, B: 20 years

Q17: Number Series - Consecutive Even Numbers (2025 - Real Question)

Problem: Which of the following is the next term in the series: 2, 6, 12, 20, 30, ?

Solution: Pattern: Differences are 4, 6, 8, 10 (consecutive even numbers) Next difference = 12 Next term = 30 + 12 = 42

Alternative pattern: n(n+1) where n starts from 1 1×2=2, 2×3=6, 3×4=12, 4×5=20, 5×6=30, 6×7=42

Answer: 42

Q18: Vocabulary - Ephemeral Synonym (2025 - Real Question)

Problem: Choose the correct synonym for “Ephemeral”:

a) Eternal b) Temporary c) Perpetual d) Endless

Solution: “Ephemeral” means lasting for a very short time, temporary. “Temporary” is the synonym.

Answer: b) Temporary

Q1: Number Series - Square Pattern (2025)

Problem: Find next number: 1, 4, 9, 16, 25, ?

Solution: Pattern: n² where n = 1, 2, 3, 4, 5… 1²=1, 2²=4, 3²=9, 4²=16, 5²=25 Next: 6² = 36

Answer: 36

Q2: Number Series - Prime Pattern (2025)

Problem: Find next number: 2, 3, 5, 7, 11, ?

Solution: Pattern: Prime numbers in sequence 2, 3, 5, 7, 11, 13… Next: 13

Answer: 13

Q3: Number Series - Fibonacci Variant (2025)

Problem: Find next number: 1, 1, 2, 3, 5, 8, ?

Solution: Pattern: Fibonacci sequence (each number is sum of previous two) 1, 1, 2, 3, 5, 8, 13… Next: 13

Answer: 13

Q4: Letter Series - Skip Pattern (2025)

Problem: Find next letter: B, E, H, K, ?

Solution: Pattern: B(+3)→E(+3)→H(+3)→K(+3)→N Next letter = N

Answer: N

Q5: Coding-Decoding - Reverse Pattern (2025)

Problem: If “ACCENTURE” is coded as “ERUTNECCA”, how is “SYSTEM” coded?

Solution: Pattern: Letters are reversed ACCENTURE → ERUTNECCA (reversed) SYSTEM → METSYS (reversed)

Answer: METSYS

Q6: Syllogism - Three Statements (2025)

Problem: Statements: 1. Some books are novels, 2. All novels are stories, 3. No story is a poem

Conclusions: I) Some books are stories, II) No novel is a poem, III) Some stories are books

Solution: From 1 and 2: Some books are stories (I follows) From 2 and 3: No novel is a poem (II follows) From I: Some stories are books (III follows)

Answer: All I, II, and III follow

Q7: Blood Relations - Complex (2025)

Problem: Pointing to a photograph, a man said, “She is the daughter of my grandfather’s only son.” How is the man related to the person in the photograph?

Solution: Grandfather’s only son = man’s father Daughter of man’s father = man’s sister So the person is the man’s sister

Answer: Sister

Q8: Direction Sense - Multiple Turns (2025)

Problem: A person walks 10m north, then 5m east, then 10m south, then 5m west. Where is he from starting point?

Solution: Net north = 10 - 10 = 0 Net east = 5 - 5 = 0 He is at the starting point

Answer: At starting point (no displacement)

Q9: Seating Arrangement - Circular (2025)

Problem: Six friends A, B, C, D, E, F sit around a circular table. A sits opposite D. B sits between A and C. E is not adjacent to A. Who sits opposite E?

Solution: In circular arrangement with 6 people, opposite pairs: (A,D), (B,E), (C,F) Since A is opposite D, and B is between A and C, and E is not adjacent to A E must be opposite B

Answer: B

Q10: Ordering & Ranking (2025)

Problem: In a queue, Ravi is 15th from front and 20th from back. How many people are in the queue?

Solution: Total = Position from front + Position from back - 1 Total = 15 + 20 - 1 = 34

Answer: 34 people

Q1: Reading Comprehension - Inference (2025)

Passage: “Cloud computing has transformed how businesses operate. Companies can now access computing resources on-demand without maintaining physical infrastructure. This has led to significant cost savings and increased flexibility.”

Question: What is the main advantage of cloud computing mentioned?

Answer: Cost savings and increased flexibility

Q2: Grammar - Parallelism (2025)

Problem: Choose the correct sentence:

a) She likes reading, writing, and to dance b) She likes reading, writing, and dancing c) She likes to read, writing, and dancing

Solution: Parallel structure requires same form: all gerunds or all infinitives. Option b maintains parallelism with all gerunds.

Answer: b) She likes reading, writing, and dancing

Q3: Vocabulary - Synonyms (2025)

Problem: Find the synonym of “MAGNIFICENT”:

a) Ordinary b) Splendid c) Small d) Ugly

Solution: Magnificent means impressively beautiful or grand, so “Splendid” is the synonym.

Answer: b) Splendid

Q4: Vocabulary - Antonyms (2025)

Problem: Find the antonym of “BRILLIANT”:

a) Bright b) Dull c) Shining d) Smart

Solution: Brilliant means very bright or intelligent, so “Dull” is the antonym.

Answer: b) Dull

Q5: Sentence Correction (2025)

Problem: Choose the correct sentence:

a) He is a honest man b) He is an honest man c) He is the honest man

Solution: “Honest” starts with a vowel sound, so “an” is used.

Answer: b) He is an honest man

Q1: C Output - Post and Pre Increment (2025)

Problem: What is the output?

int main() {
int a = 5, b = 10;
printf("%d %d", a++, ++b);
printf(" %d %d", a, b);
return 0;
}

Solution: a++ uses 5, then a becomes 6 ++b makes b = 11, uses value 11 First printf: 5 11 Second printf: 6 11

Answer: 5 11 6 11

Q2: Loop with Break (2025)

Problem: What is the output?

int main() {
int i;
for(i=1; i<=10; i++) {
if(i == 5) break;
printf("%d ", i);
}
return 0;
}

Solution: Loop executes: i=1 prints 1, i=2 prints 2, i=3 prints 3, i=4 prints 4, i=5 breaks

Answer: 1 2 3 4

Q3: Array and Pointer (2025)

Problem: What is the output?

int main() {
int arr[] = {10, 20, 30, 40};
int *p = arr;
printf("%d %d", *p, *(p+3));
return 0;
}

Solution: p points to arr[0] = 10 *p = 10 *(p+3) = arr[3] = 40

Answer: 10 40

Q4: Recursion - Sum (2025)

Problem: What is the output?

int sum(int n) {
if(n == 0) return 0;
return n + sum(n-1);
}
printf("%d", sum(5));

Solution: sum(5) = 5 + sum(4) sum(4) = 4 + sum(3) sum(3) = 3 + sum(2) sum(2) = 2 + sum(1) sum(1) = 1 + sum(0) sum(0) = 0 sum(1) = 1 + 0 = 1 sum(2) = 2 + 1 = 3 sum(3) = 3 + 3 = 6 sum(4) = 4 + 6 = 10 sum(5) = 5 + 10 = 15

Answer: 15

Q5: Java Output - String (2025)

Problem: What is the output?

public class Test {
public static void main(String[] args) {
String s1 = "Hello";
String s2 = new String("Hello");
System.out.println(s1 == s2);
System.out.println(s1.equals(s2));
}
}

Solution: s1 == s2 compares references (false, different objects) s1.equals(s2) compares content (true, same string)

Answer: false true

Q6: Python Output - List (2025)

Problem: What is the output?

def func(lst):
if len(lst) == 0:
return 0
return lst[0] + func(lst[1:])
print(func([1, 2, 3, 4]))

Solution: func([1,2,3,4]) = 1 + func([2,3,4]) func([2,3,4]) = 2 + func([3,4]) func([3,4]) = 3 + func([4]) func([4]) = 4 + func([]) func([]) = 0 func([4]) = 4 + 0 = 4 func([3,4]) = 3 + 4 = 7 func([2,3,4]) = 2 + 7 = 9 func([1,2,3,4]) = 1 + 9 = 10

Answer: 10

Q7: Pointer Arithmetic - Advanced (2025)

Problem: What is the output?

int main() {
int arr[] = {1, 2, 3, 4, 5};
int *p = &arr[2];
printf("%d %d", p[-1], p[1]);
return 0;
}

Solution: p points to arr[2] = 3 p[-1] = arr[1] = 2 p[1] = arr[3] = 4

Answer: 2 4

Q8: Nested Loops - Pattern (2025)

Problem: What is the output?

int main() {
int i, j;
for(i=1; i<=3; i++) {
for(j=1; j<=i; j++) {
printf("%d", j);
}
printf("\n");
}
return 0;
}

Solution: i=1: j=1, prints 1, newline i=2: j=1,2, prints 12, newline i=3: j=1,2,3, prints 123, newline

Answer: 1 12 123

Q9: C Code Output - Sequence Point Issue (2025 - Real Question)

Problem: What is the output of the following C code snippet?

#include <stdio.h>
int main() {
int a = 5;
printf("%d", a++ + ++a);
return 0;
}

Solution: This exhibits undefined behavior due to sequence point violations. The expression a++ + ++a modifies and accesses the variable a without an intervening sequence point, leading to undefined behavior. Different compilers may produce different outputs.

Answer: Undefined behavior (compiler-dependent, typically 12 in many compilers)

Q10: Abstract Reasoning - Shape Sequence (2025 - Real Question)

Problem: Identify the next shape in the sequence: Circle, Square, Triangle, Circle, Square, ?

Solution: The sequence repeats every three shapes: Circle, Square, Triangle After Circle and Square, the next shape is Triangle

Answer: Triangle

Q11: Pseudo Code - Simple Addition (2025 - Real Question)

Problem: What will be the output of the following pseudocode?

Begin
Set A = 10
Set B = 20
Set C = A + B
Print C
End

Solution: A = 10 B = 20 C = A + B = 10 + 20 = 30 Print C = 30

Answer: 30

Q12: Networking - Secure Protocol (2025 - Real Question)

Problem: Which of the following is a common protocol used for secure communication over the internet?

a) HTTP b) FTP c) HTTPS d) SMTP

Solution: HTTPS (HyperText Transfer Protocol Secure) is the secure version of HTTP and is used for secure communication over the internet. It uses SSL/TLS encryption.

Answer: c) HTTPS

Q13: Ratio Problem - Algebraic Expression (2025 - Real Question)

Problem: Find (7x + 4y) / (x - 2y) if x/2y = 3/2.

Solution: Given x/2y = 3/2 Cross multiplying: 2x = 6y, so x = 3y

Substituting x = 3y: (7x + 4y) / (x - 2y) = (7(3y) + 4y) / (3y - 2y) = (21y + 4y) / y = 25y / y = 25

Answer: 25

Q14: Statement & Assumption (2025 - Real Question)

Problem: Statement: “All students must submit their assignments by Friday.” Assumption: Students are aware of the deadline. Is the assumption valid?

Solution: Yes, the assumption is valid. The statement implies that students have been informed about the deadline, otherwise the instruction would be meaningless.

Answer: Yes, the assumption is valid

Q15: Cause and Effect (2025 - Real Question)

Problem: Event 1: The company reported a significant increase in profits. Event 2: The company launched a new product line. Determine the relationship.

Solution: Event 2 (launching a new product line) is likely the cause, and Event 1 (increase in profits) is the effect. Launching successful products typically leads to increased sales and profits.

Answer: Event 2 is the cause, Event 1 is the effect

Q1: Palindrome Check (2025)

Problem: Check if string is palindrome (case-insensitive).

Solution (C):

#include <string.h>
#include <ctype.h>
int is_palindrome(char str[]) {
int left = 0, right = strlen(str) - 1;
while (left < right) {
if (tolower(str[left]) != tolower(str[right]))
return 0;
left++;
right--;
}
return 1;
}

Solution (Python):

def is_palindrome(s):
s = s.lower()
left, right = 0, len(s) - 1
while left < right:
if s[left] != s[right]:
return False
left += 1
right -= 1
return True
Q2: Find Maximum Element (2025)

Problem: Find the maximum element in an array.

Solution (C):

int findMax(int arr[], int n) {
int max = arr[0];
for (int i = 1; i < n; i++) {
if (arr[i] > max)
max = arr[i];
}
return max;
}
Q3: Count Vowels (2025)

Problem: Count the number of vowels in a string.

Solution (C):

#include <ctype.h>
int countVowels(char str[]) {
int count = 0;
for (int i = 0; str[i] != '\0'; i++) {
char c = tolower(str[i]);
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')
count++;
}
return count;
}
Q4: Sum of Array Elements (2025)

Problem: Find sum of all elements in an array.

Solution (C):

int arraySum(int arr[], int n) {
int sum = 0;
for (int i = 0; i < n; i++) {
sum += arr[i];
}
return sum;
}
Q5: Linear Search (2025)

Problem: Search for an element in an array.

Solution (C):

int linearSearch(int arr[], int n, int key) {
for (int i = 0; i < n; i++) {
if (arr[i] == key)
return i;
}
return -1;
}
Q6: Reverse String (2025)

Problem: Reverse a string without using built-in functions.

Solution (C):

#include <string.h>
void reverseString(char str[]) {
int len = strlen(str);
int start = 0, end = len - 1;
while (start < end) {
char temp = str[start];
str[start] = str[end];
str[end] = temp;
start++;
end--;
}
}
Q7: Check Prime Number (2025)

Problem: Check if a number is prime.

Solution (C):

#include <math.h>
int isPrime(int n) {
if (n <= 1) return 0;
if (n <= 3) return 1;
if (n % 2 == 0 || n % 3 == 0) return 0;
for (int i = 5; i * i <= n; i += 6) {
if (n % i == 0 || n % (i + 2) == 0)
return 0;
}
return 1;
}
Q8: Find Missing Number (2025)

Problem: Find missing number in array containing numbers from 1 to n (one missing).

Solution (C):

int findMissing(int arr[], int n) {
int total = (n + 1) * (n + 2) / 2;
for (int i = 0; i < n; i++)
total -= arr[i];
return total;
}
Q9: Remove Duplicates from Sorted Array (2025)

Problem: Remove duplicates from sorted array and return new length.

Solution (C):

int removeDuplicates(int arr[], int n) {
if (n == 0) return 0;
int j = 0;
for (int i = 1; i < n; i++) {
if (arr[i] != arr[j]) {
j++;
arr[j] = arr[i];
}
}
return j + 1;
}
Q10: Check Anagram (2025)

Problem: Check if two strings are anagrams.

Solution (C):

#include <string.h>
#include <ctype.h>
int areAnagrams(char str1[], char str2[]) {
int count[256] = {0};
int len1 = strlen(str1), len2 = strlen(str2);
if (len1 != len2) return 0;
for (int i = 0; i < len1; i++) {
count[tolower(str1[i])]++;
count[tolower(str2[i])]--;
}
for (int i = 0; i < 256; i++) {
if (count[i] != 0) return 0;
}
return 1;
}
SectionCutoff (Approx)Notes
Cognitive Assessment60% (12-15/20-25)Standard cutoff
Technical Assessment60% (12-15/20-25)Standard cutoff
Coding Test1 problem solvedMust solve at least 1
Communication Assessment50% (3-5/5-10)Lower cutoff
Overall60-65%36-45/60-70 marks

Success Rate: Approximately 15-20% of candidates clear NLT

Hiring Volume

  • Expected Hires: 18,000+ freshers
  • Associate Software Engineer: 14,400+ selections
  • Software Engineer: 3,600+ selections
  • Growth: 20% increase expected

Salary Packages

  • Associate Software Engineer: ₹4.5-5 LPA
  • Software Engineer: ₹6-7 LPA
  • Advanced App Engineering Analyst: ₹8-10 LPA
  • Stable packages maintained

New Initiatives

  • Enhanced NLT platform
  • Better candidate experience
  • Faster processing
  • Innovation Challenge for advanced roles

Quantitative Aptitude

  • High Frequency: Percentage, Profit & Loss, Time & Work
  • Medium Frequency: Mixtures, Permutations, Probability
  • Focus Areas: Data Interpretation, Speed & Distance
  • Difficulty: Medium to Hard
  • New Trends: More application-based problems

Logical Reasoning

  • High Frequency: Number Series, Coding-Decoding, Syllogism
  • Medium Frequency: Blood Relations, Seating Arrangements
  • Focus Areas: Pattern Recognition, Data Sufficiency
  • Difficulty: Medium
  • New Trends: Complex multi-step reasoning problems

Verbal Ability

  • High Frequency: Reading Comprehension, Grammar Rules
  • Medium Frequency: Para Jumbles, Error Spotting
  • Focus Areas: Vocabulary, Sentence Structure
  • Difficulty: Easy to Medium
  • New Trends: Business and technology-related passages

Technical Assessment

  • High Frequency: C/C++ Output Prediction, Loop Analysis
  • Medium Frequency: Arrays, Pointers, Recursion
  • Focus Areas: Java/Python syntax, String operations
  • Difficulty: Medium
  • New Trends: More multi-language questions

Coding Problems

  • High Frequency: String Manipulation, Array Problems
  • Medium Frequency: Searching, Sorting Algorithms
  • Focus Areas: Basic Data Structures, Problem Solving
  • Difficulty: Medium to Hard
  • New Trends: Emphasis on code efficiency and edge cases
  1. Coding Section: Critical - at least 1 problem must be solved correctly
  2. Sectional Cutoffs: Must clear each section individually (50-60% per section)
  3. Time Management: Crucial for success - allocate 30-35 minutes for coding
  4. Preparation: Previous year papers very helpful - practice 20-25 papers
  5. Aptitude Focus: Strong performance in Cognitive Assessment (40-45 marks) is essential
  6. No Negative Marking: Attempt all questions - no penalty for wrong answers
  7. Updated Pattern: Slightly more emphasis on practical problem-solving and application-based questions
  8. Multi-language Support: Technical questions now include Java and Python more frequently

Based on recent candidate experiences from 2025 Accenture NLT and interviews:

2025 Interview Trends:

  • Technical interviews focus on practical problem-solving and code explanation
  • Increased emphasis on project discussions and real-world applications
  • Behavioral questions about adaptability and learning agility
  • Multi-language programming questions (Java, Python, C++)

Common 2025 Interview Topics:

  • Programming fundamentals and output prediction
  • Database concepts and SQL queries
  • System design basics for experienced candidates
  • Project deep-dives with technology stack discussions
  • Scenario-based behavioral questions

Interview Success Tips (2025):

  • Practice explaining code clearly and concisely
  • Be ready to discuss projects in detail with technologies used
  • Prepare examples demonstrating problem-solving and teamwork
  • Focus on communication skills - Accenture values clear articulation

For detailed interview experiences from Pune, Bangalore, Chennai, and other locations, visit Accenture Interview Experience page.

Previous Year Papers (2020-2025)

Complete collection of Accenture previous year question papers

View All Papers →

Based on Latest 2025 Exam Pattern:

  1. Practice Previous Year Papers: Solve 20-25 Accenture NLT papers from 2020-2025 to understand evolving patterns
  2. Master Coding Fundamentals: Focus on array manipulation, string processing, and basic algorithms
  3. Time Management: Allocate 40-45 min for Cognitive, 40-45 min for Technical, 30-35 min for Coding sections
  4. Sectional Performance: Aim for 50-60% in each section to clear cutoffs
  5. Communication Skills: Practice English speaking and comprehension regularly
  6. Mock Tests: Take timed practice tests to improve speed and accuracy
  7. Multi-language Practice: Be comfortable with at least one language (C, C++, Java, or Python)

Practice 2025 papers for current year preparation! Download the papers above and start practicing today.